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dezoksy [38]
3 years ago
14

What do we call the potential mechanical energy stored in an object when work is performed to change its shape?

Physics
1 answer:
Tom [10]3 years ago
7 0
C) kinetic energy :)
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The cheetah can reach a top speed of 114 km/h (71 mi/h). While chasing its prey in a short sprint, a cheetah starts from rest an
Mariulka [41]

Answer: a= 4.4ms-2

Displacement= 26.95 m

Explanation:

First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.

7 0
4 years ago
Read 2 more answers
A natural water molecule (H2O) in its vapor state has an electric dipole moment of magnitude, p = 6.2 x 10-30 C.m. (a) Find the
Vika [28.1K]

Answer:

a    D = 3.9 *10^{-12} \ m

b    \tau_{max} = 1.24 *10^{-25} \  N\cdot m

c   W =  2.48 *10^{-25} J

 

Explanation:

From the question we are told that

   The magnitude of electric dipole moment is  \sigma  =  6.2 *10^{-30} \ C \cdot m

     The electric field is E =  2*10^{4} \ N/C

   

The distance between the positive and negative charge center is mathematically evaluated as

     D =  \frac{\sigma }{10 e}

Where  e is the charge on one electron which has a constant value of  e = 1.60 *10^{-19} \ C

  Substituting values

     D =  \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}

      D = 3.9 *10^{-12} \ m

The maximum torque is mathematically represented as

       \tau_{max} = \sigma * E  * sin (\theta)

Here  \theta  =  90^o

This because at maximum the molecule is perpendicular to the field

    substituting values

       \tau_{max} =  6.2 *10^{-30} * 2*10^{4} sin ( 90)

       \tau_{max} = 1.24 *10^{-25} \  N\cdot m

The workdone is mathematically represented as

      W =  V_{(180)} - V_{0}

where   V_{(180)} is the potential energy at 180° which is mathematically evaluated as

     V_{(180) } = -   \sigma  * E  cos (180)

Where the negative signifies that it is acting against the  field

   substituting values

     V_{(180) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (180)

      V_{(180) } = 1.24*10^{-25} J

and

     V_{(0)} is the potential energy at 0° which is mathematically evaluated as

            V_{(0) } = -   \sigma  * E  cos (0)

   substituting values

     V_{(0) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (0)

      V_{(0) } =- 1.24*10^{-25} J

So W =  1.24 *10^{-25} - [-1.24 *10^{-25}]

    W =  2.48 *10^{-25} J

6 0
4 years ago
You throw an 18.0 N rock into the air from ground level and observe that, when it is 15.0 m high, it is traveling upward at 17.0
stellarik [79]

Answer:

Vi = 24.14 m/s

Explanation:

If we apply Law of Conservation of Energy or Work-Energy Principle here, we get: (neglecting friction)

Loss in K.E of the Rock = Gain in P.E of the Rock

(1/2)(m)(Vi² - Vf²) = mgh

Vi² - Vf² = 2gh

Vi² = Vf² + 2gh

Vi = √(Vf² + 2gh)

where,

Vi = Rock's Speed as it left the ground = ?

Vf = Final Speed = 17 m/s

g = 9.8 m/s²

h = height of rock = 15 m

Therefore,

Vi = √[(17 m/s)² + 2(9.8 m/s²)(15 m)]

Vi = √583 m²/s²

<u>Vi = 24.14 m/s</u>

4 0
3 years ago
5. An infinite wire is 3.00 cm away from and parallel to a 10 cm long wire, and each has a current of 2.50 A in the same directi
Step2247 [10]

Answer:

B=1.04*10^{-4}T

Explanation:

An infinite wire produces a magnetic field that can be computed with the formula:

B=\frac{\mu_0 I}{2\pi r}

where m0 is the magnetic permeability of vacuum (4pi*10^{-7}Tm/A), I is the current of the wire (2.50A) and r is the perpendicular distance to the wire in which B is calculated (3cm=3*10^{-2}m). By replacing we obtain:

B=\frac{(4\pi*10^{-7}Tm/A)(2.50A)}{3*10^{-2}m}=1.04*10^{-4}T

hope this helps!!

3 0
3 years ago
The bell rings and a physics student heads to class. They stop to talk to a few friends. They slow
grin007 [14]

Answer:

420m

Explanation:

Given parameters:

Time  = 5minutes

Average speed  = 1.4m/s

Unknown:

Distance covered  = ?

Solution:

Speed is the rate of change of distance with time.

 Mathematically;

              Speed  = \frac{distance}{time}  

    Distance  = speed x time

 

Insert the parameters and solve;

   Convert the time to seconds;

              1 minute = 60s

               5 minute = 5  x 60 = 300s

So,

   Insert the parameters and find the distance;

     Distance  = 300 x 1.4  = 420m

3 0
3 years ago
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