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rosijanka [135]
3 years ago
12

Which shows the correct method for solving the equation below? One-third (y minus 9) = 3 A 2-column table with 3 rows. Column 1

is labeled Solution step with entries one-third y minus 3 = 3, one-third y = 6, y = 18. Column 2 is labeled property used with entries distributive property, addition property of equality, multiplication property of equality. A 2-column table with 3 rows. Column 1 is labeled Solution step with entries one-third y minus 27 = 3, one-third y = 30, y = 10. Column 2 is labeled property used with entries distributive property, subtraction property of equality, division property of equality. A 2-column table with 3 rows. Column 1 is labeled Solution step with entries one-third y minus 3 = 1, one-third y = 4, y = 12. Column 2 is labeled property used with entries distributive property, addition property of equality, division property of equality. A 2-column table with 3 rows. Column 1 is labeled Solution step with entries one-third y minus 3 = 3, one-third y = 0, y = 0. Column 2 is labeled property used with entries distributive property, subtraction property of equality, division property of equality.
Mathematics
2 answers:
kow [346]3 years ago
4 0

Answer: I'm pretty sure it's A!

Step-by-step explanation: It's on Edge, hope this helped :)

Aleksandr-060686 [28]3 years ago
3 0

Answer:

It’s A took test

Step-by-step explanation:

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4 years ago
(csc x - 1) (csc x + 1)
victus00 [196]
<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

(a-b)(a+b)=a^2-b^2

So here:

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Thus:

(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}

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