9514 1404 393
Answer:
r = ±√47
Step-by-step explanation:
-7r^2 = -329 . . . . given
r^2 = 47 . . . . . divide both sides by -7 (multiplication property of equality)
r = ±√47 . . . . square root both sides (square root property of equality)
Answer:
Step-by-step explanation:
Givens
Length = a
Width = a + 3
Formulas
P = 2L + 2w
Area = L * w
Solution
Perimeter
P = 2L + 2w
P = 2*a + 2(a + 3) Remove the Brackets
p = 2a + 2a + 6 Combine
<u><em>P = 4a + 6</em></u>
Area
Area = L * w
Area = a (a + 3)
<u><em>Area = a^2 + 3a</em></u>
Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
12a^-4 * b^-3
a= 2 and b = -1
Can you put 2 where it says a and -1 where it says b
