Answer:
1.5 hr
16.7
Explanation:
Zero apparent weight means there's no normal force.
Sum the forces in the centripetal direction.
∑F = ma
mg = mv²/r
v = √(gr)
v = √(7.4×10⁶ m × 10 m/s²)
v = 8602 m/s
The circumference of the equator is:
C = 2πr
C = 2π (7.4×10⁶ m)
C = 4.65×10⁷ m
So the period is:
T = C / v
T = (4.65×10⁷ m) / (8602 m/s)
T = 5405 s
T = 1.5 hr
The initial speed is:
v = C / T
v = (4.65×10⁷ m) / (25 h × 3600 s/h)
v = 517 m/s
The speed increases by a factor of:
8602 m/s / 517 m/s
16.7
Answer:
c it does not move as the tire stops and applys friction
Explanation:
Answer:
Explanation:
Step one:
given data
initial velocity u= 40m/s
time taken t=3seconds
final velocity v=?
Step two:
applying the first equation of motion
v=u-gt--- (the -ve sign implies that the arrow is against gravity)
assume g=9.81m/s^2
v=40-9.81*3
v=40-29.43
v=10.57m/s
Step three:
how high the target is located
applying
s=ut-1/2gt^2
s=40*3-1/2(9.81)*3^2
s=120-88.29/2
s=120-44.145
s=75.86m
The correct answer to the question is: 78.4 N.
CALCULATION:
As per the question, the mass of the object is given as m = 8 Kg.
We are asked to calculate the force of 8 Kg object pushing up from the table.
The force pushing up from the table is nothing else than the normal reaction.
The normal reaction of the object is equal to the weight of the object as the object is simply resting on the table.
Hence, normal reaction = Weight
= mg
= 8 × 9.8 N.
= 78.4 N.
Here, g is known as acceleration due to gravity.
Hence, the force of the object pushing up from the table is 78.4 N.
Answer:
6000 kilometers
Explanation:
multiply the length value by 1000
