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son4ous [18]
4 years ago
8

A typical loaded commercial jet airplane has an inertia of 2.3×105 kg

Physics
1 answer:
GarryVolchara [31]4 years ago
6 0

Answer:

8.38\cdot 10^9 J

Explanation:

The energy that must be given to the jet is equal to its final kinetic energy.

The kinetic energy of an object is the energy possessed by an object due to its motion. It is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

In this problem:

m=2.3\cdot 10^5 kg is the mass of the jet (inertia is just another name for mass)

v = 270 m/s is the final speed of the jet

Substituting, we find the final kinetic energy of the jet:

K=\frac{1}{2}(2.3\cdot 10^5)(270)^2=8.38\cdot 10^9 J

So, this is the energy that must be given to the jet.

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An emf is induced by rotating a 1060 turn, 20.0 cm diameter coil in the Earth's 5.25 ✕ 10−5 T magnetic field. What average emf (
lara31 [8.8K]

Answer:

The average emf induced in the coil is 175 mV

Explanation:

Given;

number of turns of the coil, N = 1060 turns

diameter of the coil, d = 20.0 cm = 0.2 m

magnitude of the magnetic field,  B = 5.25 x 10⁻⁵ T

duration of change in field, t = 10 ms = 10 x 10⁻³ s

The average emf induced in the coil is given by;

E = N\frac{\delta \phi}{dt} \\\\E = N\frac{\delta B}{\delta t}A

where;

A is the area of the coil

A = πr²

r is the radius of the coil = 0.2 /2 = 0.1 m

A = π(0.1)² = 0.03142 m²

E = \frac{NBA}{t} \\\\E = \frac{1060*5.25*10^{-5}*0.03142}{10*10^{-3}} \\\\E = 0.175 \ V\\\\E = 175 \ mV

Therefore, the average emf induced in the coil is 175 mV

3 0
3 years ago
The amount of space an object takes up is its
Likurg_2 [28]

Volume.

Hope this helps.

r3t40

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3 years ago
A sea breeze occurs because warm air rises on land and moves toward the ocean to cool. The cool air then moves from the ocean to
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Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.
lina2011 [118]

Answer:

-6.0 m/s, 10.4 m/s

Explanation:

To find the x- and y- components, we have to apply the formulas:

v_x = v cos \theta

v_y = v sin \theta

where

v = 12.0 m/s is the magnitude of the vector

\theta is the angle between the direction of the vector and the positive x-axis

Here, the angle given is the angle above the negative x-axis; this means that the angle with respect to the positive x-axis is

\theta=180^{\circ} - 60^{\circ} = 120^{\circ}

So, the two components are:

v_x = (12.0 m/s) cos 120^{\circ}=-6.0 m/s

v_y = (12.0 m/s) sin 120^{\circ}=10.4 m/s

5 0
3 years ago
Calculate the Kinetic energy of an object with a mass of 15kg while sitting on a shelf that is 20m high.
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Kinetic energy is energy of motion. If the object is sitting still, then it has no kinetic energy. It doesn't matter what its mass is, or how high the shelf is.

KE = 0

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