When 1 molecule of calcium phosphate is added to water, what and how many ions are formed? remember that ions are charged and so
you must indicate the correct charge on each ion to receive credit for this question?
1 answer:
Asnwer :When 1 molecule of calcium phosphate is added to water, total 5 ions are formed 3 ions of Calcium() and 2 ions of Phosphate(
)
Explanation : When Calcium phosphate is added to water it gets dissociated into ions. Calcium phosphate () dissociates into 3 ions of Calcium
and 2 ions of Phosphate
.
Dissociation equation of calcium phosphate is :
From the dissociation equation we can conclude that total 5 ions are formed when 1 molecule of calcium phosphate is added to water.
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Number of electrons in a Ca²⁺ = 18
<h3>Further explanation </h3>In an atom there are levels of energy in the shell and sub shell
This energy level is expressed in the form of electron configurations.
Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f. The maximum number of electrons for each sub shell is
• s: 2 electrons
• p: 6 electrons
• d: 10 electrons and
• f: 14 electrons
Charging electrons in the sub shell uses the following sequence:
<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc. </em>
The element Ca has an atomic number of 20, so the number of electrons and protons (in neutral atoms) is also 20
Electron configuration of Ca : <em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s² ⇒[Ar] 4s²</em>
When Ca releases 2 electrons to gain stability (forming Ca²⁺ cations), the number of electrons becomes:
and the electron configuration (Ca²⁺ ) becomes:
<em>1s², 2s², 2p⁶, 3s², 3p⁶</em>
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