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poizon [28]
3 years ago
11

The graph of h (x) = StartAbsoluteValue x minus 10 EndAbsoluteValue + 6 is shown. On which interval is this graph increasing

Mathematics
2 answers:
k0ka [10]3 years ago
7 0

Answer:

x≥10 or x∈[10, ∞)

Step-by-step explanation:

The graph we are given is h(x) = |x-10|+6, which has the shape of a V. The vertex is at (10, 6), so to the right of the vertex, the graph is increasing.

Therefore, the graph increases during the interval x≥10 or x∈[10, ∞).

devlian [24]3 years ago
4 0
The answer is 10 because there is not negative number so the absolute value of a positive number is that number
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4 0
3 years ago
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
If A and B are independent events, P(A) = 0.25, and P(B) = 0.3, what is P(AB)?
Marrrta [24]

Answer:

P(A) = 0.25, P(B= 0.3

And if we want to find P(A \cap B) we can use this formula from the definition of independent events :

P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075

And the best option would be:

P(A \cap B) =0.075

Step-by-step explanation:

For this case we have the following events A and B and we also have the probabilities for each one given:

P(A) = 0.25, P(B= 0.3

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P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075

And the best option would be:

P(A \cap B) =0.075

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