$i=\sqrt{-1}\\\\\sqrt{-4}=\sqrt{(4)(-1)}=\sqrt4\cdot\sqrt{-1}=2i\\\\\sqrt{-25}=\sqrt{(25)(-1)}=\sqrt{25}\cdot\sqrt{-1}=5i\\\\\sqrt{-4}-\sqrt{-25}=2i-5i=-3i$

5 0

3 years ago

Read 2 more answers

What is the answer to this?

myrzilka [38]

Answer:r=3cm,diameter =6cm and C=18.84cm

Step-by-step explanation:

To find the radius,diameter and circumference according to the diagram drawn above

r=3cm

Diameter=2×3cm

d=6cm

To find the circumference

C=2πr

C=2×3.14×3cm

C=18.84cm

4 0

3 years ago

Which of the fallowing points are the solution to the equation 3x-4y-8=12. Chose all that apply (0,-5) (4,-2) (8,2) (-16,-17) (-

Virty [35]

Answer:

The solutions for the equation are:

(4,-2) and (-16,-17)

Step-by-step explanation:

Given equation:

$3x-4y-8=12$

Given points:

(0,-5), (4,-2), (8,2), (-16,-17), (-1,-8), (-40,-34)

We will check each point by plugging it in the given equation and see if it satisfies the equation or not.

(0,5)

$3(0)-4(5)-8=12$

$0-20-8=12$

$-28=12$

which is not true. Hence, not a solution.

(4,-2)

$3(4)-4(-2)-8=12$

$12+8-8=12$

$12=12$

which is true. Hence, it is a solution.

(8,2)

$3(8)-4(2)-8=12$

$24-8-8=12$

$24-16=12$

$8=12$

which is not true. Hence, not a solution.

(-16,-17)

$3(-16)-4(-17)-8=12$

$-48+68-8=12$

$20-8=12$

$12=12$

which is true. Hence, it is a solution.

(-1,-8)

$3(-1)-4(-8)-8=12$

$-3+32-8=12$

$21=12$

which is not true. Hence, not a solution.

(-40,-34)

$3(-40)-4(-34)-8=12$

$-120+136-8=12$

$8=12$

which is not true. Hence, not a solution.

6 0

3 years ago