Answer:
Step-by-step explanation:
<u>Exponential Growing
</u>
Steven currently reads 2 books a year. He wants to triple the number of books read per year. The first year he should read
By the second year, he should read
By the third year, he should read
We can clearly see there is a geometric progression of the number of books he should read for the year n. The general formula is, being B the number of books read at the year n
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
498 is approximately 500
12 is approximately 10
500/10 = 50
So, 498/12 is approximately 50.
Y=2x
so what you do is sub 2x for y in the top equation
x^2+(2x)^2=5
x^2+4x^2=5
5x^2=5
divide both sides by 5
x^2=1
sqrt both sides
x=1 or -1
sub back
y=2x
y=2(-1)
y=-2
y=2(1)
y=2
the solutions are (1,2) and (-1,-2)
