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Diano4ka-milaya [45]
1 year ago
7

In this experiment, the reaction is quenched with aqueous nahco3. what byproducts form when nabh4 reacts with water? which bypro

duct poses the greater risk? why?
Chemistry
1 answer:
igor_vitrenko [27]1 year ago
5 0

NaBH 4 reacts with water and alcohols, with the evolution of hydrogen gas and the formation of the corresponding borate, the reaction being especially fast at low pH. Nevertheless, alcohol, often methanol or ethanol, is generally the solvent of choice for sodium borohydride reductions of ketones and aldehydes.

Methanol poses a greater risk because it is metabolized into a very toxic substance i.e. formic acid and also highly poisonous.

What is Methanol?

Methanol is a promising energy carrier because, as a liquid, it is easier to store than hydrogen and natural gas. Its energy density is, however, lower than methane, per kg.

To know more about methanol go to the given link :

brainly.com/question/495179

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Name the mineral group for each of the following minerals: Group of answer choices Kyanite (Al2SiO5) Ilmenite (FeTiO3) Rhodochro
Ainat [17]

Answer:

Kyanite (Al2SiO5) - silicate

Ilmenite (FeTiO3) - Oxides

Rhodochrosite (MnCO3) - carbonate

Celestite (SrSO4) - sulphate

Chalcocite (Cu2S) -  sulphide

Explanation:

Minerals are classified according to their chemical composition. For example those that hve the CO32- ion are called carbonates and those with the SO42- ion are called sulphates while the ones with S2- ion are called sulphides

3 0
3 years ago
A/1 * B/C =D
Novay_Z [31]
<h3>Answer:</h3>

                  0.64 Moles of Propane

<h3>Explanation:</h3>

Data:

         Moles of Carbon  =  1.5 mol

         Conversion factor  =  7 mol C produces = 3 mol of Propane

Solution:

             As we know,

                7 moles of Carbon produces =  3 moles of Propane

Then,

            1.5 moles of Carbon will produce  =  X moles of Propane

Solving for X,

                     X =  (1.5 moles × 3 moles) ÷ 7 moles

                     X  =  0.6428571 moles of Propane

Or rounded to two significant figures,

                     X =  0.64 Moles of Propane

5 0
3 years ago
Choose the correct option for the redox reaction below : 8H+(aq) + MnO4-(aq) + 5Fe2+(aq) → Mn2+(aq) + 5Fe3+(aq) 4H2O(l) H+ (oxid
hodyreva [135]

Explanation:

8H+(aq) + MnO4-(aq) + 5Fe2+(aq) → Mn2+(aq) + 5Fe3+(aq) + 4H2O(l)

To determine if a substance was reduced or oxidized, the oxidation number at the reactant and product side is compared.

When oxidation occurs, an element loses electrons and its oxidation number increases (becomes more positive). When reduction occurs, an element gains electrons and its oxidation number decreases or is reduced (becomes more negative).

H+ (oxidized or reduced) Answer 1 Choose...

There is an increase in oxidation number from 0 to 1. This means H+ was oxidized.

MnO4- (oxidizing or reducing agent) Answer 2 Choose...

In chemistry, an oxidizing agent is a substance that has the ability to oxidize other substances — in other words to accept their electrons

MnO4- is a strong oxidizing agent.

Fe2+ (oxidizing or reducing agent) Answer 3 Choose...

A reducing agent means it will itself get oxidized. In  this reaction, Fe2+ is the reducing agent.

Fe2+ (oxidized or reduced) Answer 4 Choose...

Oxidized

O in MnO4- (oxidized or reduced) Answer 5 Choose...

There is no change in oxidation number of , so it was neither reduced nor was it oxidized.

Mn in MnO4- (oxidized or reduced) Answer 6 Choose...

There is a decreaase in oxidation number from +7 to +2. This means reduction.

6 0
3 years ago
A student obtains the following data: Mass of empty, dry graduated cylinder: 21.577 g Volume added of NaCl solution: 4.602 mL Ma
klasskru [66]

<u>Answer:</u> The density of NaCl solution is 3.930 g/mL

<u>Explanation:</u>

We are given:

Mass of cylinder, m_1 = 21.577 g

Mass of NaCl and cylinder combined, M = 39.664 g

Mass of NaCl, m_2 = (M-m_1)=(39.664-21.577)g=18.087g

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of NaCl = 18.087 g

Volume of NaCl solution = 4.602 mL

Putting values in above equation, we get:

\text{Density of NaCl}=\frac{18.087g}{4.602mL}\\\\\text{Density of NaCl}=3.930g/mL

Hence, the density of NaCl solution is 3.930 g/mL

7 0
3 years ago
Please help ill give brainliest
boyakko [2]

Answer: The answer to the first one is the second option and the answer for the second one is the first option.

Explanation:

5 0
2 years ago
Read 2 more answers
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