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Studentka2010 [4]
3 years ago
13

A __________ score allows a researcher to compare scores across different scales.

Physics
2 answers:
cupoosta [38]3 years ago
6 0
The correct answer should be C. standard

When you have standardization developed, then it is possible to compare scores across different scales and make sure that everything works relatively fine.
german3 years ago
4 0

Answer:

C

Explanation:

took the test :)

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A pizza parlor is considering adding taco pizza and Hawaiian pizza to its
tia_tia [17]

Answer: 79

Explanation:

7 0
3 years ago
Read 2 more answers
A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work
yawa3891 [41]

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

  • Mass of car; m = 200kg
  • Acceleration of the car; a = 0.5m/s^2
  • Distance covered by the car; d = 10m

Work done; W = \ ?

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

Work\ done = f * d

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; Force \ F = m * a

We substitute our given values into the expression

F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2

Next we substitute our values into the expression of work done above.

Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J

Therefore, the work done by the man pushing the car over the given distance is 1000J.

Learn more about work done: brainly.com/question/26115962

7 0
2 years ago
A 1056-hertz tuning fork is struck at the same time as a note on the piano and you hear 2 beats/second. You tighten the piano st
elena-14-01-66 [18.8K]

Answer:

The frequency of the piano string is <em>1059 Hz</em>.

Explanation:

The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.

As the piano string gets tightened, the frequency beat becomes 3 beats/second.

Therefore,

fb = fb = fpiano - ftuning fork\\ 3 Hz=fpiano-1056Hz\\ fpiano=1056Hz+3Hz\\ fpiano=1059Hz

6 0
4 years ago
an aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. the hole is 30mm in diameter and i
zavuch27 [327]

Answer:

ΔL = 1.011 mm

Explanation:

Let's begin by listing out the given information:

Length (L) = 600 mm = 0.6 m,

Diameter (D) = 40 mm = 0.04 m ⇒ Radius (r) = 20 mm = 0.2 m,

Area (cross sectional) = πr² = 3.14 x .02² = 0.001256 m²,

Modulus of Elasticity (E) = 85 GN/m²,

Compressive load (F) = 180 KN

Using the formula, Stress = Load ÷ Area

Mathematically,

σ = F ÷ A = 180 x 10³ ÷ 0.001256

σ = <u>143312.1 KN/m</u>²

Modulus of elasticity = stress ÷ strain

E = σ ÷ ε

ε = ΔL/L

85 x 10⁹ = 143312.1 x 10³ ÷ (ΔL/L)

ΔL = 143312.1 x 10³ ÷ 85 X 10⁹ = 1686.02 * 10⁻⁶

ΔL = L x 1686.02 * 10⁻⁶

ΔL = 0.6 * 1686.02 * 10⁻⁶ = 1011.61 x 10⁻⁶

ΔL = 1.011 x 10⁻³ m

ΔL = <u>1.011 mm</u>

∴The bar contracts by 1.011 mm

4 0
3 years ago
A roof tile falls from rest from the top of a building. An observer inside the building notices that it takes 0.28 s for the til
PIT_PIT [208]

Answer:0.246 m

Explanation:

Given

height of window (h)=1 m

Time to pass window =0.28 s

Let roof is at a distance of h_0 above window

let t be the time to cover h_0

h_0+1=\frac{g(t+0.28)^2}{2}------1

h_0=\frac{gt^2}{2}--------2

subtract 1 & 2

1=\frac{g(t+0.28)^2}{2}-\frac{gt^2}{2}

1=\frac{g}{2}\left [ \left ( 2t+0.28\right )\left ( 0.28\right )\right ]

t=0.224 s

h_0=\frac{9.8\times 0.224^2}{2}

h_0=0.246 m

5 0
3 years ago
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