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3 years ago

A __________ score allows a researcher to compare scores across different scales.

2 answers:

6 0

The correct answer should be C. standard

When you have standardization developed, then it is possible to compare scores across different scales and make sure that everything works relatively fine.

german3 years ago

4 0

Answer:

Explanation:

took the test :)

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Which state of matter has a definite volume but no definite shape

a_sh-v [17]

The answer is liquid.

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3 years ago

An object with an initial velocity of 10 m/s accelerates at a rate of 3.5 m/s2 for 8 seconds. How far will it have traveled duri

ICE Princess25 [194]

Answer:

Distance, d = 192 meters

Explanation:

We have,

Initial velocity of an object is 10 m/s

Acceleration of the object is 3.5 m/s²

Time, t = 8 s

We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :

$d=ut+\dfrac{1}{2}at^2$

$d=10\times 8+\dfrac{1}{2}\times 3.5\times 8^2\\\\d=192\ m$

So, the distance travelled by the object is 192 meters.

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3 years ago

An unknown substance is tested and found to have the following physical properties: brittle fair conductor of electricity dull (

nikklg [1K]

The answer is <span>metalloid </span>

6 0

3 years ago

Read 2 more answers

How efficient are the small and large scale solar-power systems used in individual homes and industrial settings? What is the en

Leviafan [203]

Answer:

$\color{Blue}\huge\boxed{Answer}$

<em>The potential environmental impacts associated with solar power—land use and habitat loss, water use, and the use of hazardous materials in manufacturing—can vary greatly depending on the technology, which includes two broad categories: photovoltaic (PV) solar cells or concentrating solar thermal plants (CSP).</em>

Explanation:

I just answer the second question

4 0

3 years ago

SCALCET8 3.9.018.MI. A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the

Firlakuza [10]

Answer:

The length of his shadow is decreasing at a rate of 1.13 m/s

Explanation:

The ray of light hitting the ground forms a right angled triangle of height H, which is the height of the building and width, D which is the distance of the tip of the shadow from the building.

Also, the height of the man, h which is parallel to H forms a right-angled triangle of width, L which is the length of the shadow.

By similar triangles,

H/D = h/L

L = hD/H

Also, when the man is 4 m from the building, the length of his shadow is L = D - 4

So, D - 4 = hD/H

H(D - 4) = hD

H = hD/(D - 4)

Since h = 2 m and D = 12 m,

H = 2 m × 12 m/(12 m - 4 m)

H = 24 m²/8 m

H = 3 m

Since L = hD/H

and h and H are constant, differentiating L with respect to time, we have

dL/dt = d(hD/H)/dt

dL/dt = h(dD/dt)/H

Now dD/dt = velocity(speed) of man = -1.7 m/s ( negative since he is moving towards the building in the negative x - direction)

Since h = 2 m and H = 3 m,

dL/dt = h(dD/dt)/H

dL/dt = 2 m(-1.7 m/s)/3 m

dL/dt = -3.4/3 m/s

dL/dt = -1.13 m/s

So, the length of his shadow is decreasing at a rate of 1.13 m/s

5 0

2 years ago