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kotykmax [81]
3 years ago
13

A positively charged particle 1 is at the origin of a Cartesian coordinate system, and there are no other charged objects nearby

. You need the electric field magnitude at the position (1.00 nm , 8.00 nm ) to be zero, so that no electric force is exerted on any charged object placed at that location.
Where would you need to place particle 2 if it carried the same charge as particle 1?

Physics
1 answer:
8090 [49]3 years ago
3 0

Answer:

P=(2 nm, 8mn)

Explanation:

Given :

Position of positively charged particle at origin, O=(0\ nm,0\ nm)

Position of desired magnetic field, D\equiv(1\ nm,8\ nm)

Magnitude of desired magnetic field, E=0\ N.C^{-1}

Let q be the positive charge magnitude placed at origin.

<u>We know the distance between the two Cartesian points is given as:</u>

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>

\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }

\therefore (1-0)^2+(8-0)^2=r^2

r^2=65\ nm

r=\sqrt{65}

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the  given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

x=2\times 1=2\ nm

and

y=2\times 8=16\ nm

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Answer:

\phi=4.52 rad

Explanation:

From the question we are told that

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Frequency of antenna RadiationF_r=120 MHz \approx 120*10^6Hz

Distance from receiver d_r=150m

Intensity of Receiver i= 10

Distance difference of the receiver b/w antenna's (r^2-r^1)=1.8m

Generally the equation for Phase difference \phi is mathematically given by

 \phi=\frac{2\pi}{\frac{c}{f_r}} *(r^2-r^1)

 \phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8

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<h3>  \phi=4.52 rad</h3>

Therefore phase difference f between the two radio waves produced by this path difference is given as

\phi=4.52 rad

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3 years ago
Which of the following is a consequence of the special theory of relativity?
aleksandr82 [10.1K]

Answer:

D.

Explanation:

Specifically, Special Relativity showed us that space and time are not independent of one another but can be mixed into each other and therefore must be considered as the same object, which we shall denote as space-time. The consequences of space/time mixing are: time dilation. and length contraction.

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Write a numerical expression for the emissive intensity (in W/m^2.sr) coming out of a tiny hole in an enclosure of surface tempe
stiks02 [169]

Answer:

6.0 × 10^{11} W/m^{2}

Explanation:

From Wien's displacement formula;

Q = e AT^{4}

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The emissive intensity = \frac{Q}{A} = eT^{4}

Given from the question that: e = 0.6 and T = 1000K, thus;

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A dockworker loading crates on a ship finds that a 21-kg crate, initially at rest on a horizontal surface, requires a 73-N horiz
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1) Static friction coefficient: 0.355

The crate is initially at rest. The crate remains at rest until the horizontal pushing force is less than the maximum static frictional force.

The maximum static frictional force is given by

F_s = \mu_s mg

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\mu_s is the static coefficient of friction

m = 21 kg is the mass of the crate

g = 9.8 m/s^2 is the acceleration due to gravity

The horizontal force required to set the crate in motion is 73 N: this means that this is the value of the maximum static frictional force. So we have

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Now the crate is in motion: this means that the kinetic friction is acting on the crate, and its magnitude is

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F = 55 N

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