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Advocard [28]
3 years ago
9

Helppppppp! Find the length of PQ if PQR is an isosceles triangle with PQ ≈ QR.​

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

43

Step-by-step explanation:

3x + 10 = 5x - 12

       10 = 2x - 12

      22 = 2x

        x = 11

check:

33 + 10 = 55 - 12

43 = 43

correct

x = 11 so bring this into 3x + 10

we get 43

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For which value of c is the line y=3x+c a tangent to the parabola with equation y=x^2-5x+7
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Equating the y's:-

3x + c = x^2 - 5x + 7

x^2  - 8x +7 - c = 0

If y = 3x + c is a tangent then there  will be duplicate solutions to this equation 
That is the discriminant b^2 - 4ac = 0. So we have:-

(-8)^2 - 4 * 1 * (7 -c)  = 0
64 -28 + 4c = 0
4c  = - 36

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At the football game they sold $4 pizzas and $2 sodas, which made the school $260. The number of sodas sold was 5 more than thre
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3 years ago
Se the FOIL method to evaluate the expression: (5+2)(4-5)
DaniilM [7]

The FOIL <em>method</em> is a method of <u>expanding</u> two given <u>brackets</u> by following the required <u>steps</u>. Thus using the FOIL <em>method</em>, the required answer is: -7

<em>Expansion</em> of <u>brackets</u> may be done using different <em>methods</em>, but these <em>methods</em> would give the same answer. Some <em>methods</em> that can be used are the <u>binomial</u> expansion method, FOIL method, etc.

The FOIL <u>method</u> is a <em>shortened</em> form of the<u> steps</u> required for the process. These required <u>steps</u> are <u>First</u>, <em>Outside</em>, <em>Inside</em>, and <u>last.</u>

Thus to <u>expand</u> the given <em>brackets</em> in the question, we have;

(5+2)(4-5) = 5(4 - 5) + 2(4 - 5)

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(5+2)(4-5) = -7

Thus using the FOIL <u>method</u>, the <u>answer</u> to the question is -7.

<em>Quick check</em>: (5+2)(4-5) = (7)(-1)

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For more clarifications on expansion of brackets using the FOIL method, visit: brainly.com/question/1592629

#SPJ 1

3 0
2 years ago
You want to buy some apples. Look at the scales below.
timofeeve [1]

Answer: no scale

Step-by-step explanation:

3 0
3 years ago
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\dfrac{x}{24\sqrt{2}}=\cos45^\circ\\\\\\\dfrac{x}{24\sqrt{2}}=\dfrac{\sqrt{2}}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{2}\cdot\sqrt{2}\\\\2x=24\cdot2\quad|:2\\\\\boxed{x=24}
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3 years ago
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