Radium-221 has a half-life of 30 s. how long will it take for 95% of a sample to decay
this would be 2.22 seconds
Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.
Answer:-
Solution:- It is a volume unit conversion problem where we are asked to convert the volume from to microliters.
We know that:
= 1 mL
and,
Let's use these conversions factors for the desired conversion using dimensional as:
=
So, the answer is .
Answer:
1/16
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 269 years
Time (t) = 1076 years
Fraction remaining =?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 269 years
Time (t) = 1076 years
Number of half-lives (n) =?
n = t / t½
n = 1076 / 269
n = 4
Thus, 4 half-lives has elapsed.
Finally, we shall determine the fraction of the original amount remaining. This can be obtained as follow:
Let N₀ be the original amount.
Let N be the amount remaining.
Number of half-lives (n) = 4
Fraction remaining (N/N₀ ) =?
N = 1/2ⁿ × N₀
N = 1/2⁴ × N₀
N = 1/16 × N₀
Divide both side by N₀
N/N₀ = 1/16
Thus, the fraction of the original amount remaining is 1/16
Explanation:
Dinitrogen trioxide is a nitrogen oxide. Nitrogen trioxide appears as a blue liquid with a sharp, unpleasant chemical odor.
Description: Dinitrogen trioxide is a nitrogen oxide.ChEBINitrogen trioxide appears as ...
Synonyms: Dinitrogen trioxideNITROGEN TRIOXIDENitrogen oxide (N2O3)10544-7...
Molecular Formula: N2O3
Molecular Weight: 76.012 g/mol