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brilliants [131]
3 years ago
8

Because electron delocalization stabilizes a compound, if the only way electrons can be moved is away from the most electroneagt

ive atom, that is better than no electron delocalization at all.
a. True
b. False
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
5 0
It’s is false because it is
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How many moles of phosphoric acid are there in 658 grams of phosphoric acid?
vovangra [49]
<span>The molecular formula for phosphoric acid is H3PO4 and has 97.994 grams per mol. In a sample of 658 grams of phosphoric acid, there are 6.71 mols of phosphoric acid.</span>
8 0
3 years ago
Chemistry student needs 15.0 g of painting for an experiment by consulting the CRC handbook of chemistry and physiology the stud
nalin [4]

Answer:

v = 23.96 cm³

Explanation:

Given data:

Mass = 15.0 g

Density = 0.626 g/cm³

Volume = ?

Solution:

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

d = m/v

v = m/d

v = 15 g / 0.626 g/cm³

v = 23.96 cm³

8 0
3 years ago
Which statement is true about matter?
sergeinik [125]

Answer:

C

Explanation:

This is because matter is anything that has mass and occupies space.Therefore the space occupied by matter is volume

6 0
3 years ago
Determine the number of moles of C5H12 that are contained in 357.4 g of the compound.
AlladinOne [14]

Answer: 4.96 moles

Explanation:

C5H12 is the chemical formula for pentane, the fifth member of the alkane family.

Given that,

number of moles of C5H12 = ?

Mass in grams = 357.4 g

Molar mass of C5H12 = ?

To get the molar mass of C5H12, use the atomic mass of carbon = 12g; and Hydrogen = 1g

i.e C5H12 = (12 x 5) + (1 x 12)

= 60g + 12g

= 72g/mol

Now, apply the formula

Number of moles = Mass / molar mass

Number of moles = 357.4g / 72g/mol

= 4.96 moles

Thus, 4.96 moles of C5H12 that are contained in 357.4 g of the compound.

4 0
3 years ago
Niobium-91 has a half-life of 680 years. After 2,040 years, how much niobium-91 will remain from a 300.0-g sample? 3 g 18.75 g 3
Vadim26 [7]
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
7 0
3 years ago
Read 2 more answers
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