Answer:
Lead(II) sulfate
Explanation:
This looks like a double displacement reaction, in which the cations change partners with the anions.
The possible products are
Pb(NO₃)₂ (aq)+ Na₂SO₄(aq) ⟶PbSO₄(?) + 2NaNO₃(?)
To predict the product, we must use the solubility rules. Two important ones for this question are:
- Salts containing Group 1 elements are soluble.
- Most sulfates are soluble, but PbSO₄ is an important exception.
Thus, NaNO₃ is soluble and PbSO₄ is the precipitate.
Answer:
Please find the explanation to this question below.
Explanation:
Answer: low temperature
Explanation:-
S.I or M.K.S is a system for defining physical units as meter, kilogram, second, ampere, kelvin or celcius, candela, and mole together with a set of prefixes to indicate multiplication or division by a power of ten for measuring length, mass, time , current, temperature and amount of substance respectively.
Given :
lake length = 563 kilometers = 
High temperature =
Low temperature =
annual precipitation =762 mm= 
Thus low temperature in units of Fahrenheit is not an S.I unit of measurement.
<h2>Question:- </h2>
A solution has a pH of 5.4, the determination of [H+].
<h2>Given :- </h2>
- pH:- 5.4
- pH = - log[H+]
<h2>To find :- concentration of H+</h2>
<h2>Answer:- Antilog(-5.4) or 4× 10-⁶</h2>
<h2>Explanation:- </h2><h3>Formula:- pH = -log H+ </h3>
Take negative to other side
-pH = log H+
multiple Antilog on both side
(Antilog and log cancel each other )
Antilog (-pH) = [ H+ ]
New Formula :- Antilog (-pH) = [+H]
Now put the values of pH in new formula
Antilog (-5.4) = [+H]
we can write -5.4 as (-6+0.6) just to solve Antilog
Antilog ( -6+0.6 ) = [+H]
Antilog (-6) × Antilog (0.6) = [+H]

put the value in equation
![{10}^{ - 6} \times 4 = [H+] \\ 4 \times {10}^{ - 6} = [H+]](https://tex.z-dn.net/?f=%20%7B10%7D%5E%7B%20-%206%7D%20%20%20%5Ctimes%204%20%3D%20%5BH%2B%5D%20%5C%5C%204%20%5Ctimes%20%20%20%7B10%7D%5E%7B%20-%206%7D%20%20%3D%20%5BH%2B%5D)