First we need to find the number of moles of hydrogen gas formed Zn + 2HCl ---> ZnCl₂ + H₂ stoichiometry of Zn to H₂ is 1:1 the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol assuming Zn to be the limiting reactant number of Zn moles reacted = number of H₂ moles formed therefore number of H₂ moles formed = 0.0367 mol
we can use ideal gas law equation to find the pressure PV = nRT P - pressure V - Volume - 450 x 10⁻⁶ m³ n - number of moles - 0.0367 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature - 32 °C + 273 = 305 K substituting these values in the equation P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K P = 206.8 kPa pressure is 206.8 kPa
