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pshichka [43]
3 years ago
5

In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

Chemistry
1 answer:
Yuliya22 [10]3 years ago
6 0
He is using filtration technique

It's a technique which is used for separation of solids and fluids by putting them through a medium which allow only fluid to pass through, leaving the solids (in this case the soil) alone.

The fluid that passed is called the filtrate
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The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. How does the gas pressure change?
liberstina [14]

Answer:

It increases by a factor of eight

Explanation:

When temperature is held constant, gas pressure changes according the volume, in undirectly proportion.

Volume increases →  Pressure decreases

Volume decreases → Pressure increases

As volume gas, was reducted from 4L to 0.5L, it was reduced by 1/8, so the pressure gas was increased by a factor of eight.

5 0
3 years ago
Mechanical advantage = load/_______​
arlik [135]

Answer:

Mechanical advantage = load/<u>effort</u>

Explanation:

Mechanical advantage is like a ratio of load to effort and many machines like pulleys depend on this relationship between load and effort for it to work.

8 0
3 years ago
Read 2 more answers
Classify the following compounds as binary ionic, ternary ionic, or molecular.
Alborosie

Answer:bro u already have an answer why are you asking?

Explanation:

3 0
3 years ago
Which of the answer choices correctly describes a phase change that occurs when a solid transitions directly into a gas state wi
mihalych1998 [28]
The change directly from solid to gas is called sublimation
5 0
3 years ago
If you use 1 mole of NaOH, how much NaAl(OH)4 is produced
abruzzese [7]
Answer:
             81.97 g of NaAl(OH)₄

Solution:
              The reaction for the preparation of Sodium Aluminate from Aluminium Metal and NaOH is as follow,

                 2 NaOH  +  2 Al  +  6 H₂O    →    2 NaAl(OH)₄  +  3 H₂

According to this equation,

          2 Moles of NaOH produces  =  163.94 g (2 mole) of NaAl(OH)₄
So,
       1 Mole of NaOH will produce  =  X g of NaAl(OH)₄

Solving for X,
                     X  =  (1 mol × 163.94 g) ÷ 2 mol

                     X  =  81.97 g of NaAl(OH)₄
5 0
3 years ago
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