Ask question

Ask question

All categories

2 years ago

15

As NaOH is added to an aqueous solution, the pH will 1. decrease. 2. Not enough information is given to solve the problem. 3. be

unaffected because NaOH is not an acid. 4. increase or decrease depending on whether the initial pH is higher or lower than 7. 5. increase

1 answer:

Dominik [7]2 years ago

4 0

PH increases when you add NaOH because it’s a strong base.

You might be interested in

A sample of ammonia ^NH3h gas is completely decomposed to nitrogen and hydrogen gases over heated iron wool. If the total pressu

icang [17]

Answer : The partial pressure of $N_2$ and $H_2$ is, 216.5 mmHg and 649.5 mmHg

Explanation :

According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.

Formula used :

$p_i=X_i\times p_T$

$X_i=\frac{n_i}{n_T}$

So,

$p_i=\frac{n_i}{n_T}\times p_T$

where,

$p_i$ = partial pressure of gas

$X_i$ = mole fraction of gas

$p_T$ = total pressure of gas

$n_i$ = moles of gas

$n_T$ = total moles of gas

The balanced decomposition of ammonia reaction will be:

$2NH_3\rightarrow N_2+3H_2$

Now we have to determine the partial pressure of $N_2$ and $H_2$

$p_{N_2}=\frac{n_{N_2}}{n_T}\times p_T$

Given:

$n_{N_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg$

$p_{N_2}=\frac{1}{4}\times (866mmHg)=216.5mmHg$

and,

$p_{H_2}=\frac{n_{H_2}}{n_T}\times p_T$

Given:

$n_{H_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg$

$p_{H_2}=\frac{3}{4}\times (866mmHg)=649.5mmHg$

Thus, the partial pressure of $N_2$ and $H_2$ is, 216.5 mmHg and 649.5 mmHg

5 0

3 years ago

What are parts of the nervous system

Vlad1618 [11]

Answer:

the brain and the spinal cord are the two main parts.

6 0

3 years ago

How do the particles that are dispersed in a colloid differ from the particles suspended in a suspension?

Fed [463]

Answer:B, the colloid particles are larger.

PLEASE GIVE BRAINLIEST AND WATCH OUT BEHIND YOU

5 0

3 years ago

Determine the molar concentration of HCL required if 40cm^3 of HCL is reacted with 36g of magnesium via this equation.

Art [367]

The answer is in the photo.

4 0

3 years ago

What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of

jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl

58.44 is the molar mass of NaCl

m=0.1711 mol NaCl/2 kg H2O

m=0.085557837

7 0

3 years ago