Formula
V/T = V1/T1
Givens
V = 430 L
T = - 42 °C = - 42 + 273 = 231°K
V1 = ??
T1 = 18°C + 273 = 291°K
The pressure is a constant.
Solution
420/231 = V1/291 Multiply by 291
420*291 / 231 = V1
V1 = 122220 / 231
V1 = 521.1 L
Answer:
K = 0.0003 s⁻¹
Explanation:
The reaction is
2N₂O₅ = 4NO₂ + O₂
The equilibrium is
![K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]](https://tex.z-dn.net/?f=K%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7Bdt%7D%20%5C%5C%5Cint%5Climits%5Ey_x%20%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7B%7D%20%5C%2C%20%3D-2k%5Cint%5Climits%5Et_0%20%7Bdt%7D%20%5C%2C%5C%5Cln%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-2kt%2Bln%5BN_%7B2%7D%20O_%7B5%7D%20%5D)
a plot is attached
From the plot, the slope is -0.0006
-2 * K = -0.0006
K = 0.0003 s⁻¹
Kinetic energy=1/2*mass*velocity²
=1/2*291*49
=7129.5 Joules
Answer:
Particle density is the volumetric mass of the solid soil. It differs from bulk density because the volume used does not include pore spaces. Particle density represents the average density of all the minerals composing the soil.
Hope that helps
Combustion! CH4, which is methane, reacts with oxygen to form carbon dioxide. (For future reference, if a compound is reacted with ONLY oxygen it is sure to be a combustion reaction)
