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EastWind [94]
3 years ago
14

Formula for these neutral ionic compounds?

Chemistry
1 answer:
Vladimir [108]3 years ago
8 0
1. CaO (-2)+(+2) =0
2.Na3As 3(+1) +(-3)=0
3.B(NO2)3 (+3)+3(-1)=0
4.(NH4)2SO4. 2(+1)+(-2)=0
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Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.
Makovka662 [10]

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

  • experience a change in its temperature, which involves sensible heat,
  • undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

  • Q: amount of heat
  • m: mass
  • L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

  • Q: amount of sensible heat  
  • m: body mass
  • c: specific heat of the substance
  • ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is  4.184 \frac{J}{g*C}:

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 \frac{J}{g*C})* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 \frac{J}{g}:

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 \frac{J}{g}) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is  2.02 \frac{J}{g*C} :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 \frac{J}{g*C})*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

<u><em>The total amount of energy required is 25,515.2 J.</em></u>

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3 years ago
What are the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions
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 <span>This is rather a case of purification of impure copper or extraction of Cu from its alloy. You need to place the impure copper rod on the positive electrode (Anode) usualyy made of carbon rod, whereby oxidation reaction takes place: Cu (s) -------> Cu2+ (aq) + 2e- That is to say the impure cooper dissolves into solution. The copper (II) ions move to the negative electrode (cathode) usually made of pure copper rod. At the cathode, the Cu2+ ions are reduced : Cu2 (aq)+ + 2e- -----> Cu(s). That is to say the copper (II) ions are deposited as solid copper atoms onto the cu-rod electrode. In this way impure copper is deposited as pure copper onto the copper cathode</span>
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I am a subatomic particle <br> that is positively charged what am I?
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<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em><u>Proton</u></em><em><u>.</u></em>

<em><u>Additional</u></em><em><u> </u></em><em><u>Information</u></em><em><u>:</u></em>

<em><u>There</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>three</u></em><em><u> </u></em><em><u>types</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>subatomic</u></em><em><u> </u></em><em><u>particles</u></em><em><u>.</u></em><em><u> </u></em><em><u>They</u></em><em><u> </u></em><em><u>are</u></em><em><u>:</u></em>

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<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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What's the mass shown?
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Answer:

The mass number of an atom is its total number of protons and neutrons. Atoms of different elements usually have different mass numbers , but they can be the same.

Explanation:

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