1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
crimeas [40]
3 years ago
6

Meeting URL: https://meet.google.com/goq-wpub-frp

Physics
2 answers:
kolbaska11 [484]3 years ago
4 0

Answer:

<h2>That's great</h2>

Explanation:

<h2>let me join</h2>
WITCHER [35]3 years ago
4 0
It’s not letting me





? What do I do
You might be interested in
A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa
Elanso [62]

Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

\frac{C_2}{C_1} = \frac{2.3}{1.15}

a ) when charge remains constant

energy = \frac{q^2}{2C}

q is charge and C is capacity

energy stored initially E₁= \frac{q^2}{2C_1}

energy stored finally E₂ = \frac{q^2}{2C_2}

\frac{E_1}{E_2} = \frac{C_2}{C_1} = \frac{2.3}{1.15}

E_2 = \frac{1.15}{2.3 } \times E_1

= \frac{1.15}{2.3 } \times 8.38

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

\frac{E_2}{E_1} = \frac{C_2}{C_1}

\frac{E_2}{8.38} = \frac{2.3}{1.15}

E_2 = 16.76 .

8 0
3 years ago
Calculate the speed of a proton after it accelerates from rest through a potential difference of 350 V.
AVprozaik [17]

The speed of a proton after it accelerates from rest through a potential difference of 350 V is 25.86 \times 10^4 ~m/s.

Initial velocity of the proton u = 0

Given potential difference \Delta V = 350V

let's assume that the speed of the proton is v,

Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge q when accelerated with a potential difference \Delta V is,

    U = q \Delta V

Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy  P.E must be equal to gain in Kinetic Energy K.E</em> i.e

\Delta K = \Delta V

If the initial and final velocity of the proton is u and v respectively then,

change in Kinetic Energy  \implies  \Delta K = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}mv^2 - 0

change in Potential Energy \implies \Delta U = q\Delta V

from conservation of energy,

             v= \sqrt{\frac{2q\Delta V}{m}}

so,         v = \sqrt{\frac{2\times 350 \times 1.6\times 10^{-19}}{1.67 \times 10^{-27}}

                = 25.86 \times 10^4 ~m/s

To read more about the conservation of energy, please go to brainly.com/question/14668053

7 0
1 year ago
Daniel takes his two dogs, Pauli the Pointer and Newton the Newfoundland, out to a field and lets them loose to exercise. Both d
DedPeter [7]

Answer:

Explanation:

3.4 m/s due North, -1.1 m/s due East

7 0
3 years ago
Will give you brainliest pls help
ExtremeBDS [4]

1. All the relevant resistors are in series, so the total (or equivalent) resistance is the sum of the resistances of the resistors: 20 Ω + 80 Ω + 50 Ω = 150 Ω [choice A].

2. The ammeter will read the current flowing through this circuit. We can find the ammeter reading using Ohm's law in terms of the electromotive force provided by the battery: I = ℰ/R = (30 V)(150 Ω) = 0.20 A [choice C].

3. The voltmeter will measure the potential drop across the 50 Ω resistor, i.e., the voltage at that resistor. We know from question 2 that the current flowing through the resistor is 0.20 A. So, from Ohm's law, V = IR = (0.20 A)(50 Ω) = 10. V, which will be the voltmeter reading [choice F].

4. Trick question? If the circuit becomes open, then no current will flow. Moreover, even if the voltmeter were kept as element of the circuit, voltmeters generally have a very high resistance (an ideal voltmeter has infinite resistance), so the current moving through the circuit will be negligible if not nil. In any case, the ammeter reading would be 0 A [choice B].

4 0
2 years ago
The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act
marta [7]

Answer:

B.

Explanation:

According to CDC, if you’re doing moderate-intensity activity, you can talk but not sing during the activity.

8 0
3 years ago
Read 2 more answers
Other questions:
  • An object is accelerating if it is moving____. circle all that apply. ​
    10·1 answer
  • In which activity is no work done?
    15·2 answers
  • In what changes of state do atoms lose energy? Check all that apply
    11·1 answer
  • a box is pulled by by two forces. the first force is 50 newtons west and the second force is 20 newtons east. find the resultant
    13·1 answer
  • Suppose these waves represent the sound of a siren on a passing ambulance. Which wave represents the sound of the siren after it
    5·2 answers
  • When water is boiled at a pressure of 2.00 atm, the heat of vaporization is 2.20×106J/kg2.20×10
    13·1 answer
  • How does technology make sustainability more difficult?
    7·2 answers
  • Order these sounds from loudest (1) to softest (4). airplane: whisper: crowd at sporting event: rainfall:
    15·2 answers
  • Figure 13 shows a child’s toy . The toy hangs from a hook in the ceiling.
    12·1 answer
  • I got 13 min to do 20 problems helpppp
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!