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3 years ago

Meeting URL: https://meet.google.com/goq-wpub-frp

Physics

2 answers:

kolbaska11 [484]3 years ago

4 0

Answer:

<h2>That's great</h2>

Explanation:

WITCHER [35]3 years ago

4 0

It’s not letting me

? What do I do

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Consider an electron that is 100 m from an alpha particle ( = 3.2 x 10-19 C). (Enter the magnitudes.) (a) What is the electric f

scoundrel [369]

Answer:

a) $E=2.88*10^{-13}N/C$

b) $E=1.44*10^{-13}N/C$

c) $F=4.61*10^{-32}N$

Explanation:

The definition of a electric field produced by a point charge is:

$E=k*q/r^2$

<u>a)Electric Field due to the alpha particle:</u>

$E=k*q_{alpha}/r^2=9*10^9*3.2*10^{-19}/(100)^2=2.88*10^{-13}N/C$

<u>b)Electric Field due to the electron:</u>

$E=k*q_{electron}/r^2=9*10^9*1.6*10^{-19}/(100})^2=1.44*10^{-13}N/C$

<u>c)Electric Force on the alpha particle, on the electron:</u>

The alpha particle and electron feel the same force magnitude but with opposite direction:

$F=k*q_{electron}*q_{alpha}/r^2=9*10^9*1.6*10^{-19}*3.2*10^{-19}/(100)^2=4.61*10^{-32}N$

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3 years ago

Give an explaination to the following formula p=I^2R

Art [367]

Answer:

Explanation:

This is the equation that defines the power consumed by an electrical circuit. It is normally defined as the product of the voltage applied (V) times the current (I) that runs through it. And in the case of a resistive circuit (resistors in the circuit totaling a certain resistance R), one can use Ohm's law to replace the voltage by the product of the current (I) times the resistance (R), obtaining then the square of the current:

$P=V*I=(I*R)*I=I^2 * R$

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2 years ago

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Answer:

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