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3 years ago

When a boat is floating on a lake, the buoyant force on the boat is equal to:

Physics

2 answers:

Natali [406]3 years ago

8 0

The gravitational pull of the boat in the water

vova2212 [387]3 years ago

8 0

The buoyant force on a floating object is equal to the object's weight.

So the vertical forces on the object are balanced. That's a big part
of the reason why it's just sitting there and not accelerating up or down.

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A wave travels along a stretched horizontal rope. The vertical distance from crest to trough for this wave is 13 cm and horizont

shepuryov [24]

Answer:

(A) The wavelength of this wave is $56\; \rm cm$ .

(B) The amplitude of this wave is $6.5\; \rm cm$ .

Explanation:

Refer to the diagram attached. A point on this wave is at a crest or a trough if its distance from the equilibrium position is at a maximum.

The amplitude of a wave is the maximum displacement of each point from the equilibrium position. That's the same as the vertical distance between the crest (or the trough) and the equilibrium position.

On the diagram, the distance between the two gray dashed lines is the vertical distance between a crest and a trough. According to the question, that distance is $\rm 13\; \rm cm$ for the wave in this rope.
On the other hand, the distance between either gray dashed line and the black dashed line is the distance between a crest (or a trough) and the equilibrium position. That's the amplitude of this wave.

Therefore, the amplitude of the wave is exactly $\displaystyle \frac{1}{2}$ the vertical distance between a crest and a trough. Hence, for the wave in this question,

$\begin{aligned}& \text{Amplitude}\\ &= \frac{1}{2} \times (\text{Vertical distance between crest and trough}) \\ &= \frac{1}{2} \times 13\;\rm cm = 6.5\; \rm cm\end{aligned}$ .

The wavelength of a transverse wave is the same as the minimum (horizontal) distance between two crests or two troughs. That's twice the horizontal distance between a crest and a trough in the same period.

$\begin{aligned}& \text{Wavelength}\\ &= 2 \times (\text{Horizontal distance between adjacent crest and trough}) \\ &= 2 \times 28\;\rm cm = 56\; \rm cm\end{aligned}$ .

4 0

3 years ago

Tension force refers to an object being pulled tight from both ends. Think about pulling a rope or string. This type of force is

coldgirl [10]

Answer:

No. Tension Force Elastic Force

1. A force transmitted through a wire, rope or a string when it is pulled from opposite ends is known as a tension force. A force that allows an object to return its original shape after being stretched or compressed is known as an elastic force.

2. Example: Pulling a rope from two opposite ends

When a rope is pulled from two opposite ends, a tension is generated in rope.

Due to this tension, a force is transmitted through a rope which is known as a tension force. Example: Stretching a rubber band

When a rubber band is stretched, it gets stretched easily due to its elastic nature.

The more a rubber band is stretched, the more force it will exert to return back to its original shape.

This force is known as an elastic force.

Explanation:

5 0

3 years ago

A 1.2 kg block sliding on a horizontal frictionless surface is attached to a horizontal spring with k =480 N/m. Let x be the dis

Angelina_Jolie [31]

Answer:

(a). The frequency is 3.18 Hz.

(b). The amplitude of the block's motion is 0.255 m.

(c). The expression for x as a function of time is $x=0.255\cos(19.9 t+\dfrac{\pi}{2})$

Explanation:

Given that,

Mass of block = 1.2 kg

Spring constant = 480 N/m

Speed = 5.2 m/s

We need to calculate the frequency

Using formula of frequency

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{480}{1.2}}$

$f=3.18\ Hz$

The frequency is 3.18 Hz.

(b). We need to calculate the amplitude of the block's motion

Using relation of equation of amplitude and kinetic energy

$\dfrac{1}{2}\times kA^2=\dfrac{1}{2}\times mv^2$

Put the value into the formula

$\dfrac{1}{2}\times500\times A^2=\dfrac{1}{2}\times1.2\times(5.2)^2$

$A^2=\dfrac{1.2\times(5.2)^2}{500}$

$A=\sqrt{\dfrac{1.2\times(5.2)^2}{500}}$

$A=0.255\ m$

The amplitude of the block's motion is 0.255 m.

(c). We need to write the expression for x as a function of time

$x=A\cos(\omega t+\phi)$

Put the value into the equation

$x=0.255\cos(19.9 t+\dfrac{\pi}{2})$

The expression for x as a function of time is $x=0.255\cos(19.9 t+\dfrac{\pi}{2})$

Hence, This is the required solution.

6 0

3 years ago

The change in resistance of a metallic conductor at temperature below 0°C is

Aleks [24]

Answer:

A: Linear

Explanation:

Formula for Resistance of a metallic conductor is given as;

R = R_o(1 + αΔT)

Where;

R_o is the original resistance

R is the final resistance after change in temperature

ΔT is change in temperature

α is coefficient of linear expansion

Now, from the formula given, we can see that the change in resistance is directly proportional to the change in temperature.

Thus, the higher the final temperature, the more the change in resistance and the lower the final temperature, the lesser the change in resistance.

Thus, for temperature less than zero, since the change is resistance is directly proportional to the temperature, it means it follows a linear relationship.

5 0

3 years ago

The momentum of a car traveling in a straight line at 20 m/s is 24,500 kg•m/s. What is the cars mass?

Molodets [167]

Answer:

p=mv

p=given=24500kg-m/sec

m=?

v=20m/sec

m=p/v

=24500kg-m/sec÷20m/sec

=1225kg=ans

5 0

3 years ago