When C-C is having a triple bond the hybridization is sp. But I am not sure how to relate that to the linear shape.
Answer:
Initially 
of nitrogen dioxide were in the container .
Explanation:
Volume of the container at low pressure and at room temperature =
Number of moles in the container = 
After more addition of nitrogen gas at the same pressure and temperature.
Volume of the container after addition = 
Number of moles in the container after addition=
Applying Avogadro's law:
(at constant pressure and temperature)
Initially of nitrogen dioxide were in the container .
Answer:
Yes, the investigations will reach similar conclusions about the reactivity of H2 and Cl2
Explanation:
1. The law of multiple proportions says that when elements form compounds, the proportions of the elements in those chemical compounds can be expressed in small whole number ratios. This means that regardless of whether 1000 times more of the products are used, the reactivity of the products is established by the chemical reaction
2. The law of multiple proportions is an extension of the law of definite composition, which states that compounds will consist of defined ratios of elements.
3. A reaction with more reactants will need more care because more products are produced, which can be toxic
4. H2 and Cl2 reactivity does not depend on the quantities but the chemical properties of each compound
Answer:
In order to grow a plant one should first look and compare the climate of the local environment in which the plant grows with the climate in which the person is planning to grow the plant. Thus, in the given case, Becky should do more examinations on the kind of environment and the kind of soil in which the flower is grown generally. By finding the kind of soil, one should perform some brisk assessment on the structure and composition of the soils that will permit one to find that whether or not the planting location is suitable for the growth of the flower.
Answer:
Ca(OH)₂ (aq) + 2NH₄Cl (aq) → CaCl₂ (aq) + 2NH₃ (g) + 2H₂O (l)
Ca²⁺ + 2OH⁻ + 2NH₄⁺ + 2Cl⁻ → Ca⁺² + 2Cl⁻ + 2NH₃ (g) + 2H₂O (l)
2OH⁻ + 2NH₄⁺ → 2NH₃ (g) + 2H₂O (l)
