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UNO [17]
3 years ago
6

a warehouse worker pushes a crate across a concrete floor, the force he applies is not perfectly horizontal, as shown in the ima

ge below. if the coeffcient fo kinetic friction between the crate and concrete floor is .5, what is the net force on the crate?
Physics
1 answer:
olga2289 [7]3 years ago
8 0

Answer:

Explanation:

If F is the applied force and θ is the applied angle from horizontal with positive angle below the horizon

Fnet = Fcosθ - μ(mg + Fsinθ)

The only variable you've actually given us is the friction coefficient.

You'll have to plug your own numbers in.

Remember, if the applied force is acting towards the floor, the normal force is increased as will be the friction force. The net force will decrease.

If the applied force is acting upward, the θ angle will be negative and the normal force is decreased along with the friction force. The net force will increase.

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Explain what white light is and what it’s composed of.
Nataly_w [17]

Answer and Explanation:

The light that comes from the sun is called white light. Actually white light is a mixture of lights of different colors. When we look at the rainbow we can see the colors that make up the white light. This phenomenon, known as dispersion, occurs when a ray of composite light is refracted (refraction) in some medium, and its constituent colors are separated.

I attached you I picture where you can see this process

Basically, when the light passes through a glass prism, the different wavelengths that make up the beam of light travel inside it at different speeds and curl differently when entering and leaving resulting in a beam deviated from the initial direction and with its separate components.

5 0
3 years ago
What is heredity? i think its physics
Rashid [163]
It's the passing of traits/characteristics from the parent(s) to the offspring(kids).<span>This is how offspring cells become predisposed to the genes/traits of the parent cells</span>.
8 0
3 years ago
Calculate the solubility (in m units) of ammonia gas in water at 298 k and a partial pressure of 2.50 bar . the henry's law cons
Eduardwww [97]
Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
 Mathematically it can be formulated as
 C = H⨯P
 being:
 C: the molar concentration of dissolved gas A,
 P: the partial pressure of it
 H: Henry's constant
 Substituting:
 C = P * H
 C = (2.50 * 0.9869) * 58.0
 C = 143.1
 Answer:
 the solubility (in m units) is
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8 0
3 years ago
A 37.5 kg box initially at rest is pushed 4.05 m along a rough, horizontal floor with a constant applied horizontal force of 150
vodomira [7]

Answer:

a) 607.5 J

b) 160.531875 J

c)  0 J

d)  0 J

e) 2.925 m\s

Explanation:

The given data :-

  • Mass of the box ( m ) = 37.5 kg.
  • Displacement made by box ( x ) = 4.05 m.
  • Horizontal force ( F ) = 150 N.
  • The co-efficient of friction between box and floor ( μ ) = 0.3
  • Gravitational force ( N ) = m × g = 37.5 × 9.81 = 367.875

Solution:-

a) The work done by applied force ( W )

W = force applied × displacement = 150 × 4.05 = 607.5 J

b)  The increase in internal energy in the box-floor system due to friction.

Frictional force ( f ) = μ × N = 0.3 × 367.875 = 110.3625 N

Change in internal energy = change in kinetic energy.

ΔU = ( K.E )₂ - ( K.E )₁

Since the initial velocity is zero so the  ( K.E )₁ = 0  

ΔU = ( K.E )₂ = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

c) The work done by the normal force .

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

d)  The work done by the gravitational force.

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

e) The change in kinetic energy of the box

( K.E )₂ - ( K.E )₁ = ( K.E )₂ - 0 = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

f) The final speed of the box

( K.E )₂ = 160.531875 J = 0.5 × 37.5 × v²

v² = 8.56

v = 2.925 m\s.

5 0
4 years ago
A car rounds a flat curve and experiences a centripetal force directed toward the center of the curve and perpendicular to the d
Usimov [2.4K]
<h2>Answer:</h2>

If a car is rounding a flat curve, it experiences a centripetal force that pulls it towards the center of the circle it is rotating in.

Now,

The centripetal force can be balanced by the centrifugal force caused due to the acceleration of the body at the high speed which counters the centripetal force and in turn <u>prevents the car from slipping down the curve.</u>

So,

If the car doesn't hit the gas then the <em><u>car will fall down from the curve</u></em> as the Centripetal force will exceed the Centrifugal force of the car.

However, if the car doesn't hit the brake then the <em><u>car will maintain it's position on the flat curve</u></em> track as the centrifugal force will counter the effect of centripetal force directed towards the center.

3 0
3 years ago
Read 2 more answers
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