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Shalnov [3]
2 years ago
11

A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k

g/s, what is the terminal speed of the marble in m/s?.
Physics
1 answer:
mixer [17]2 years ago
8 0

The terminal speed of the marble is 0.588 m/s.

Given:

We know that,

F = mg                          ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                            ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                             .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k        

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

​

Learn more about the calculation of force, refer to:

brainly.com/question/15562875

#SPJ4

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marta [7]

Explanation:

1. Low-energy particle detector: This particle detector measures the charged particles of the solar winds.

2. Magnetometer boom: This device measures magnetic fields produced by astronomical bodies.

3. High-gain antenna: A HGA has a narrow radio beam that is used to enhance the strength of signal. They simply amplify the weak signals.

4. Photopolarimeter: This is an instrument that is used to measure the strength and intensity and polarization of reflected light.

4 0
3 years ago
A student exerts a force of 500 n pushing a box 10 m across the floor in 4 s. how much work does the student perform?
gregori [183]
Work = Force * distance
W = Fd

Given F = 500 N, d = 10 m
W = (500)(10)
W = 5000 J

The work done is 500 Joules. The time of 4 s is irrelevant in this case.
6 0
3 years ago
A luggage handler pulls a 20.0 kgkg suitcase up a ramp inclined at 32.0 ∘∘ above the horizontal by a force F⃗ F→ of magnitude 16
Nuetrik [128]

Answer:

a)    W₁ = 8242.2 J, b)      W₁ = 8242.2 J , c)  W₃ = 0 , d)  W₄ = -189.51 J  ,

f) v = 27.24 m / s

Explanation:

a) Work is defined by

         W = F. d ​​= F d sin θ

where angle is between force and displacement

n this case the suitcase is going up and the outside F is parallel to the plane, so the angle is zero and the cosine is 1

         W = F d

           

Let's calculate

         W = 169 3.8

          W₁ = 8242.2 J

b) the gravitational force is vertical so it has an angle with respect to the horizontal parallel to the plane of

           θ’= 90 - θ

           θ'= 90-32 = 58º

           

           W = m g d thing θ ’

            W = 20 9.8 3.8 thing (180 + tea ’) =

            W = 744.8 cos (180 + 32)

            W₂ = -631.6 J

c) The normal work, as it has 90º with respect to the displacement, its work is zero

         W₃ = 0

d) the work of the friction force

           

Let's write Newton's second law the Y axis

         N- Wy = 0

         Cos 32 = Wy / W

          N = W cos 32

The expression for friction force is

         fr = μ N

         fr = μ mg cos 32

         fr = 0.300 20 9.8 cos (32)

         fr = 49.87 N

The work of the friction force

         W = fr d cos 180

         W₄ = -49.87 3.8

          W₄ = -189.51 J

 

E) The total work

         W = W₁ + W₂ + W₃ + W₄

         W = 8242.2- 631.6 + 0 -189.51

          W_total = 7421.09 J

F) Usmeosel theorem of work and energy

          W = ΔK

          W = ΔK = ½ m v² - 0

          v =√ 2W / m

          v = √ (2 7421.09 / 20)

          v = 27.24 m / s

5 0
3 years ago
When a gas is heated, it absorbs 196 joules of heat from the surroundings. At the same time, the gas expands, doing pressure-vol
timurjin [86]

Answer:

(a) q positive; w negative.

(b) ΔE = -126 J

(c) E and ΔE

Explanation:

<em>(a) Determine whether the amounts of heat (q) and work (w) exchanged should have positive or negative signs. heat (q) positive negative work (w) positive negative</em>

By convention, when the system absorbs heat from the surroundings, its sign is positive, that is, q = 196 J.

By convention, when the system exerts work on the surroundings, its sign is negative, that is, w = -322 J.

<em>(b) Calculate the change in internal energy (ΔE) of the gas. J</em>

The change in internal energy (ΔE) can be calculated using the following expression.

ΔE = q + w

ΔE = 196 J + (-322 J) = -126 J

<em>(c) Determine whether one or more of the following is a state function: </em>

<em> internal energy (E) of a system, </em>

<em>change in internal energy (ΔE) of a system, </em>

<em>heat (q) absorbed or released by a system, </em>

<em>work (w) done on or by a system.</em>

<em />

E and ΔE are state functions (they only depend on the states of the gas), whereas q and w depend on the trajectory.

7 0
3 years ago
Please answer quickly
PSYCHO15rus [73]

Answer:

theory is cxorrect

Explanation:

6 0
3 years ago
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