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Shalnov [3]
2 years ago
11

A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k

g/s, what is the terminal speed of the marble in m/s?.
Physics
1 answer:
mixer [17]2 years ago
8 0

The terminal speed of the marble is 0.588 m/s.

Given:

We know that,

F = mg                          ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                            ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                             .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k        

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

​

Learn more about the calculation of force, refer to:

brainly.com/question/15562875

#SPJ4

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