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Leokris [45]
3 years ago
9

Need a bf or gf fake or reallll i dont care you can just take my points but .............. yea

Chemistry
2 answers:
sergejj [24]3 years ago
5 0

Answer:

umm I dont think this is an app to find a boy or gf :/

Explanation:

Mrac [35]3 years ago
3 0

Answer:

Hi

Explanation:

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Can all matter be categorized as elements?
AfilCa [17]

Answer:

heyy, I hope this helps! In short words yes.

5 0
3 years ago
Three-quarters of the elements are..
Dennis_Churaev [7]

Answer:

metals

Explanation:

Approximately three-quarters of all known chemical elements are metals. The most abundant varieties in the Earth's crust are aluminum,... Gold (Au), chemical element, a dense lustrous yellow precious metal of Group 11 (Ib), Period 6, of the periodic table.

8 0
4 years ago
A gas occupies a volume of 50.0 mL at 100K and 630 mmHg. At what temperature would
rodikova [14]
PV / T = P'V' / T'

V = V'

P / T = P' / T'

P = 630 mmHg
T = 100 K
P' = 1760 mmHg
T' = ?

630 / 100 = 1760 / T'

T' = 1760 / 6,3

T' = 279,36 K

T' ≈ 280 K
3 0
3 years ago
Which compounds are distinguished by an oxygen bridge between two carbon chains?
sergiy2304 [10]
I think ethers are being referred to in this questions since an ether is defined by having a oxygen atom that is directly bonded to carbons on both sides.

I hope this helps.  Let me know if you any further questions or if you anything to be clarified.
3 0
3 years ago
Given the following values for the change in enthalpy (deltaH) and entropy (deltaS), which of the following processes can occur
Shtirlitz [24]

Answer:

Option A and B

Explanation:

(a) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = Delta H – T * DS

Substituting the given values, we get –  

Delta G = -84 -298 *(125/1000) = -121.25  KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(b) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = -125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G =-84 -298 *(-125/1000) = -46.75 KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(c) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = 84 -298 *(125/1000) = +46.75 KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

(d) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G = 84 -298 *(-125/1000) = + 121.25  KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

6 0
3 years ago
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