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Answer:
M.Mass = 3.66 g/mol
Data Given:
M.Mass = M = ??
Density = d = 0.1633 g/L
Temperature = T = 273.15 K (Standard)
Pressure = P = 1 atm (standard)
Solution:
Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.
P V = n R T ---- (1)
Also, we know that;
Moles = n = mass / M.Mass
Or, n = m / M
Substituting n in Eq. 1.
P V = m/M R T --- (2)
Rearranging Eq.2 i.e.
P M = m/V R T --- (3)
As,
Mass / Volume = m/V = Density = d
So, Eq. 3 can be written as,
P M = d R T
Solving for M.Mass i.e.
M = d R T / P
Putting values,
M = 0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm
M = 3.66 g/mol
The collision of the molecules between the hydrogen molecule or H2, and an iodine molecule or I2, provided there would be a sufficient energy is that the system would eventually undergo a chemical change wherein a new chemical compound would be formed from these two molecules.
There are seven periods with eighteen columns in the periodic table.
The effusion rate is 1.125 cm/sec for ammonia.
How to find effusion rate ?
Effusion rate (r1) HCl = 43.2 cm/min
Molar mass (m2) NH3 =17.04g/mole
Molar mass (m1) HCl =36.46g/mole
- Substitute the molar masses of the gases into Graham's law and solve for the ratio.
firstly convert 43.2 cm/min into cm/sec i.e., 0.72 cm/sec
Then,
0.72/r2 =√17.04/36.46
r2= 1.125 cm/sec
Hence, the rate of diffusion of ammonia is 1.125 times faster than the rate of diffusion of hydrogen chloride.
learn more about effusion here:
brainly.com/question/2097955
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