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laiz [17]
3 years ago
9

What volume in kiloliters will a sample of Bay water occupy if it has a volume of 125 ml?

Chemistry
2 answers:
Mamont248 [21]3 years ago
6 0
This question is basically asking us to convert the volume from mL to kL.

We can do this by setting up a multiplication problem and cancelling out units:

\frac{125mL}{1}* \frac{1L}{1000mL} * \frac{1kL}{1000L}  =1.25* 10^{-4}kL

So now we know that the Bay water will occupy 1.25x10^-4 kL.
Sergeu [11.5K]3 years ago
5 0

Answer: 0.125\times 10^{-3}kL.

Explanation:

Volume of the gas is defined as the space occupied by a substance. It is expressed in units like cm^3, m^3 , L and ml.

All these units of volume are inter convertible.

We are given:

Volume of the gas = 125ml

Converting this unit of volume into 'L' by using conversion factor:

1ml=0.001L

125ml=\frac{0.001}{1}\times 125=0.125L

1L=0.001kL

Thus 0.125L=\frac{0.001}{1}\times 0.125=0.125\times 10^{-3}kL

Thus the volume in kilo Liters would be 0.125\times 10^{-3}.

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Calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting tota
Ghella [55]

Answer:

(a) ΔS_{sys}  = 2.881 J/K; ΔS_{sur}  = -2.881 J/K; total change in entropy = 0

(b)ΔS_{sys}  = 2.881 J/K; ΔS_{sur}  = 0 ; total change in entropy = 2.881 J/K

(c) ΔS_{sys}  = 0 ; ΔS_{sur}  = 0 ; total change in entropy = 0

Explanation:

In the given problem, we need to calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting total change in entropy, when a sample of nitrogen gas of mass 14 g at 298 K and 1.00 bar doubles its volume. We have the following variable:

mass (m) = 14 g

Temperature = 298 K

Pressure = 1.00 bar

Initial volume = V_{1}

Final volume = V_{2} = 2V_{1}

(a) Change in entropy of the system ΔS_{sys} = nRIn\frac{V_{2} }{V_{1} }

where R = 8.314 J/(mol*K)

n = number of moles = mass/molar mass = 14/ 28 = 0.5 moles

ΔS_{sys} = 0.5*8.314*ln2 = 2.881 J/K

Change in entropy of the surrounding ΔS_{sur} = -2.881 J/K

Therefore, for a reversible process, the total change in entropy = ΔS_{sys}+ΔS_{sur} = 2.881 - 2.881 = 0

(b) Because entropy is a state function, we use the same procedure as in part (a). Thus, ΔS_{sys}  = 2.881 J/K

Since surrounding does not change in this process ΔS_{sur} = 0.

total change in entropy = ΔS_{sys}+ΔS_{sur} = 2.881 - 0 = 2.88 J/K

(c) For an adiabatic reversible expansion, q(rev) = 0, thus:

ΔS_{sys}  = 0

Since heat energy is not transferred from the system to the surrounding

ΔS_{sur}  = 0

total change in entropy = ΔS_{sys}+ΔS_{sur} = 0

6 0
3 years ago
How much of a 24-gram sample of Radium-226 will remain unchanged at the end of three half-life periods?
shutvik [7]

Answer:

The right answer is "3 g".

Explanation:

Given:

Initial mass substance,

M_0=24 \ g

By using the relation between half lives and amount of substances will be:

⇒ M=\frac{M_0}{2^n}

        =\frac{24}{2^3}

        =3 \ g

Thus, the above is the correct answer.

8 0
3 years ago
Will a horse galloping in a field produce and average velocity of zero
motikmotik

Answer:

No

Explanation:

Depending on the mass of the horse and the speed, velocity will change.

5 0
3 years ago
What is the hardest mineral listed here? <br> A. quartz B. calcite C. gypsum D. corundum
a_sh-v [17]
The answer would be D. The only minerals harder than corundum is diamond.
3 0
3 years ago
Read 2 more answers
Write a balanced equation for the reaction<br>between ammonia and sulfuric acid?​
Slav-nsk [51]

Balanced equation for the reaction between ammonia and sulphuric acid is:

Explanation:

2NH3+H2SO4→(NH4)2SO4

I hope it'll help you...

8 0
2 years ago
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