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laiz [17]
3 years ago
9

What volume in kiloliters will a sample of Bay water occupy if it has a volume of 125 ml?

Chemistry
2 answers:
Mamont248 [21]3 years ago
6 0
This question is basically asking us to convert the volume from mL to kL.

We can do this by setting up a multiplication problem and cancelling out units:

\frac{125mL}{1}* \frac{1L}{1000mL} * \frac{1kL}{1000L}  =1.25* 10^{-4}kL

So now we know that the Bay water will occupy 1.25x10^-4 kL.
Sergeu [11.5K]3 years ago
5 0

Answer: 0.125\times 10^{-3}kL.

Explanation:

Volume of the gas is defined as the space occupied by a substance. It is expressed in units like cm^3, m^3 , L and ml.

All these units of volume are inter convertible.

We are given:

Volume of the gas = 125ml

Converting this unit of volume into 'L' by using conversion factor:

1ml=0.001L

125ml=\frac{0.001}{1}\times 125=0.125L

1L=0.001kL

Thus 0.125L=\frac{0.001}{1}\times 0.125=0.125\times 10^{-3}kL

Thus the volume in kilo Liters would be 0.125\times 10^{-3}.

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The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con
bonufazy [111]

<u>Answer:</u> The concentration of radon after the given time is 3.83\times 10^{-30}mol/L

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=3.82days

Putting values in above equation, we get:

k=\frac{0.693}{3.82}=0.181days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = 0.181days^{-1}

t = time taken for decay process = 3.00 days

[A_o] = initial amount of the reactant = 1.45\times 10^{-6}mol/L

[A] = amount left after decay process =  ?

Putting values in above equation, we get:

0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}

[A]=3.83\times 10^{-30}mol/L

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7 0
3 years ago
Question 6 (3 points)
olga55 [171]

Answer:

Explanation:

Given parameters:

Molarity of KOH = 0.26M

Volume of H₂SO₄ = 19.76mL

Molarity of H₂SO₄ = 0.20M

Unknown:

Volume of KOH = ?

Solution:

This is a neutralization reaction in which an acid reacts with a base to produce salt and water:

         H₂SO₄     +     2KOH      →    K₂SO₄    +     2H₂O

 We solve from the known to the unknown in the reaction.

The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:

       Number of moles of acid = molarity x volume

       Number of moles of acid = 19.76 x 0.20 = 3.95mol

From the balanced reaction equation:

      1 mole of acid reacts with 2 moles of the bases KOH

     3.95mole of acid would react with 3.95moles x 2 of the base

  Number of moles of reacting base = 7.90moles

To find the volume of base;

  Volume of base = \frac{number of moles of base}{molarity}

   Volume = \frac{7.90}{0.26} = 30.40mL

Learn more:

Neutralization brainly.com/question/6447527

#learnwithBrainly

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