Answer: n= 3, l= 0 , m= 0 and s=[/tex]\frac{-1}{2}[/tex]
Explanation:
Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....
Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
Magnetic quantum number : It describes the orientation of the orbital. It is represented as 'm'. The value of m ranges from -l to +l.
Spin quantum number: It describes the spin of the electron. It is represented as 's'. The value of s can be +1/2 or -1/2
Thus electron enters 3s orbital , thus n= 3, l= 0 , m= 0 and s=[/tex]\frac{-1}{2}[/tex]
The electrical charge of an atom having 15 proton, 14 neutrons and 16 electrons is -1. The correct option is D.
What is an atom?
An atom is the smallest unit of any matter which comprises of central nucleus and electrons revolving around the nucleus in definite energy shells. The atom is made up of protons, neutrons and electrons.
The electrical charge of an atom can be calculated as,
Charge of an atom = number of protons - number of electrons
Charge = 15 - 16 = -1.
The neutrons are neutral and do not contribute to the charge, the protons are positively charged and electrons are negatively charged in an atom.
Therefore, the charge of an atom with 15 protons, 14 neutrons and 16 electrons is -1. The correct answer is option D.
To learn more about atom click on the given link brainly.com/question/6258301
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Answer:
the first one I believe is right but I could be wrong.
Answer: sorry I’m not sure
Odjri:
Answer:
Cu2+(aq) + 2OH-(aq) => Cu(OH)2(s)
Explanation:
Use of aqueous sodium hydroxide is a precipitation reaction to test for anions or cations. Aqueous sodium hydroxide in a precipitate test forms a insoluble precipitates along with some colors characteristics.
Aqueous sodium hydroxide (NaOH) when mixed with copper(II) (Cu2+) forms a blue precipitate. The formula is as follows:
Cu2+(aq) + 2OH-(aq) => Cu(OH)2(s)
