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Ierofanga [76]
3 years ago
8

Write balanced, net ionic equations for the following precipitation, acidn base, or gasn forming reactions. Include states of ma

tter. Hint: You should write the molecular equation first to predict the products. a) mixing aqueous solutions of iron (III) chloride and lithium sulfide b) mixing aqueous solutions of sodium acetate and ammonium phosphate c) mixing aqueous solutions of perchloric acid and potassium hydroxide d) mixing aqueous solutions of ammonia and nitric acid e) mixing aqueous solutions of nitrous acid and sodium hydroxide f) adding aqueous hydroiodic acid to solid calcium carbonate g) Problems c) through f) are acid- base reactions. Comment on the differences in the net ionic equations for these reactions.
Chemistry
1 answer:
dybincka [34]3 years ago
5 0

Answer:

Explanation:

a ) 2FeCl₃ + 3Li₂S  = Fe₂S₃ ( s )  + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b  )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ +  3NH₄⁻  +  PO₄⁺³  = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄  + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ +  K⁺ + OH⁻  =  k⁺  ClO₄⁻  + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃  + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ +  H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

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A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
What is an acid<br>Define the term reactivity action<br>What is a compound​
valentinak56 [21]

Answer:

Acids are water-soluble and acidic chemical compounds, often expressed as the general formula HₓA.

6 0
3 years ago
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If you wanted to find a sample of fermium,which has an atomic mass of 100,where would i look???
frutty [35]

If you wanted to find a sample of fermium,which has an atomic mass of 100 I would look deep under the earth

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The recommended calcium intake for teenagers is 1300mg per day. A glass of milk contains 305mg of calcium. One glass contains a
aalyn [17]

305 x 4 = 1220.

1/4 of 304 = 76.

1220 + 76 = 1296.

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What is the concentration of water in liquid <br><br> (Percent)
scZoUnD [109]

Hello!

Reading the worksheet shows you how to find the concentration of liquid water in a substance, but when converting a decimal to a percentage, remember that ALL percentages are out of 100, so, we multiply the decimal by 100 to convert it into a percentage.

Liquid A: total amount: 10 millimeters & amount of water: 7 millimeters

7/10 = 0.7 × 100 = 70%

Liquid B: total amount: 100 millimeters & amount of water: 92 millimeters

92/100 = 0.92 × 100 = 92%

Liquid C: total amount: 15 millimeters & amount of water: 13 millimeters

13/15 = 0.867 × 100 = 86.7%

Liquid D: total amount: 28 millimeters & amount of water: 22 millimeters

22/28 = 0.786 × 100 = 78.6%

<u>Final answers</u>:

  • Liquid A: 70%
  • Liquid B: 92%
  • Liquid C: 86.7%
  • Liquid D: 78.6%
6 0
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