The car's average acceleration would be 1.25m/s^2 or 1.25meters/second/second. That looks to be the fourth one you've listed.
Answer:
The answer is B
Explanation:
The line spectrum shows distinct light different energies and wavelengths
The equivalent capacitance (
) of an electrical circuit containing four capacitors which are connected in parallel is equal to: A. 21 F.
<h3>The types of circuit.</h3>
Basically, the components of an electrical circuit can be connected or arranged in two forms and these are;
<h3>What is a parallel circuit?</h3>
A parallel circuit can be defined as an electrical circuit with the same potential difference (voltage) across its terminals. This ultimately implies that, the equivalent capacitance (
) of two (2) capacitors which are connected in parallel is equal to the sum of the individual (each) capacitances.
Mathematically, the equivalent capacitance (
) of an electrical circuit containing four capacitors which are connected in parallel is given by this formula:
Ceq = C₁ + C₂ + C₃ + C₄
Substituting the given parameters into the formula, we have;
Ceq = 10 F + 3 F + 7 F + 1 F
Equivalent capacitance, Ceq = 21 F.
Read more equivalent capacitance here: brainly.com/question/27548736
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answer: transverse and longitudinal
Explanation:
a. The velocity of the wind as a vector in component form will be represented as v vector:
![v=30j](https://tex.z-dn.net/?f=v%3D30j)
b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector
![u=475i](https://tex.z-dn.net/?f=u%3D475i)
c. The true velocity of the jet as a vector will be represented as w:
![w=u+v](https://tex.z-dn.net/?f=w%3Du%2Bv)
![w=475i+30j](https://tex.z-dn.net/?f=w%3D475i%2B30j)
d. The true speed of the jet will be calculated as:
![IwI=\sqrt{(475)^2+(30)^2}](https://tex.z-dn.net/?f=IwI%3D%5Csqrt%7B%28475%29%5E2%2B%2830%29%5E2%7D)
![IwI=\sqrt{225625+900}](https://tex.z-dn.net/?f=IwI%3D%5Csqrt%7B225625%2B900%7D)
![IwI=\sqrt{226525}](https://tex.z-dn.net/?f=IwI%3D%5Csqrt%7B226525%7D)
![IwI=476 mi/h](https://tex.z-dn.net/?f=IwI%3D476%20mi%2Fh)
e. The direction of the jet will be:
![tita=tan^{-1}\frac{30}{475}](https://tex.z-dn.net/?f=tita%3Dtan%5E%7B-1%7D%5Cfrac%7B30%7D%7B475%7D)
![tita=tan^{-1}(0.0632)](https://tex.z-dn.net/?f=%20tita%3Dtan%5E%7B-1%7D%280.0632%29)
![tita=3.62degrees,or,N86.38degreesS](https://tex.z-dn.net/?f=tita%3D3.62degrees%2Cor%2CN86.38degreesS)