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Volgvan
3 years ago
10

What is the distance between the points (4, 9) and (4, 2)? A) 2 B) 5 C) 7 D) 8

Mathematics
1 answer:
Aneli [31]3 years ago
8 0
The distance between the points are B)5
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1 4th plus 5 8th equals
Finger [1]
These two have different denominators, so you find the least common multiple. This problem goes to be 2/8+5/8, which equals 7/8。
8 0
3 years ago
How do I answer this question?​
Novay_Z [31]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle equals 180 degrees, therefore,

180 = m<1 + m<2 + m<3

180 - m<3 = m<1 + m<2

But, we also know that m<4 + m<3 = 180 degrees.

180 = m<3 + m<4

180 - m<3 = m<4

Both m<4 and m<1 + m<2  equals 180 - m<3

m<4 = m<1 + m<2

5 0
3 years ago
A total of $2100 for a house painting job is to be divided between two painters in the ratio of 3 to 4. How much does each paint
kakasveta [241]
\bf 2100\qquad 3:4\qquad \cfrac{3}{4}\implies \cfrac{3\cdot \frac{2100}{3+4}}{4\cdot \frac{2100}{3+4}}\implies \cfrac{3\cdot 300}{4\cdot 300}\implies \cfrac{900}{1200}
4 0
3 years ago
The average length of a ladybug can range from 0.08 to 0.4 inches. Find two lengths that are within the given span.Write them as
Alenkinab [10]
The average length of a ladybug can range from 0.08 to 0.4 inches.

So two lengths within the given span are 0.1 inch and 0.3 inches.

In  \: fraction: \\  \\ 0.1 \: inch =  \frac{1}{10}  \: inch \\  \\ 0.3 \: inch =  \frac{3}{10}  \: inch
7 0
3 years ago
Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60
anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

L=5W-60 (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

Area=W*L=W*(5W-60) (Equation #2)

Since the Area of the yard is 800 ft^2, then equation #2 turns into:

800=W*(5W-60)

Now, we rearrange this equation:  

800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0

We can divide the equation by 5 :

W^2-12W-160=0

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since (-20)*8=160 and -20+8=-12. The equation factorised looks like this:

(W-20)(W+8)=0

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

5*20-60=40

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0
3 years ago
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