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3 years ago

What is the distance between the points (4, 9) and (4, 2)? A) 2 B) 5 C) 7 D) 8

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

The distance between the points are B)5

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1 4th plus 5 8th equals

Finger [1]

These two have different denominators, so you find the least common multiple. This problem goes to be 2/8+5/8, which equals 7/8。

8 0

3 years ago

How do I answer this question?

Novay_Z [31]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle equals 180 degrees, therefore,

180 = m<1 + m<2 + m<3

180 - m<3 = m<1 + m<2

But, we also know that m<4 + m<3 = 180 degrees.

180 = m<3 + m<4

180 - m<3 = m<4

Both m<4 and m<1 + m<2 equals 180 - m<3

m<4 = m<1 + m<2

5 0

3 years ago

A total of $2100 for a house painting job is to be divided between two painters in the ratio of 3 to 4. How much does each paint

kakasveta [241]

$\bf 2100\qquad 3:4\qquad \cfrac{3}{4}\implies \cfrac{3\cdot \frac{2100}{3+4}}{4\cdot \frac{2100}{3+4}}\implies \cfrac{3\cdot 300}{4\cdot 300}\implies \cfrac{900}{1200}$

4 0

3 years ago

The average length of a ladybug can range from 0.08 to 0.4 inches. Find two lengths that are within the given span.Write them as

Alenkinab [10]

The average length of a ladybug can range from 0.08 to 0.4 inches.

So two lengths within the given span are 0.1 inch and 0.3 inches.

$In \: fraction: \\ \\ 0.1 \: inch = \frac{1}{10} \: inch \\ \\ 0.3 \: inch = \frac{3}{10} \: inch$

7 0

3 years ago

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0

3 years ago