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3 years ago

13

Sebastian wants to write the chemical formula for phosphorus tetraoxide. He identifies the chemical symbols as P and O. Which ad

ditional step will he take in his process?
identify the elements involved as potassium and oxygen

add a subscript of 4 after the O

write the chemical symbols, in order, as OP

use the prefix tetra before oxygen

1 answer:

denis23 [38]3 years ago

6 0

Answer:

The answer is B

Explanation:

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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam

MAXImum [283]

Explanation:

The given data is as follows.

Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence, moles of NaOH in 97 ml = $\frac{0.1090 \times 97}{1000}$

= $10.573 \times 10^{-3} mol$

Moles of HCl in 21.00 ml = $\frac{0.2060 \times 21}{1000}$

= $4.326 \times 10^{-3}$ mol

Therefore, total moles of NaOH that reacted are as follows.

$10.573 \times 10^{-3} mol$ - $4.326 \times 10^{-3} mol$

= $6.247 \times 10^{-3}$ mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

$\frac{6.247 \times 10^{-3}}{3}$

= $2.082 \times 10^{-3}$ mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

$2.082 \times 10^{-3} mol \times 40 g/mol$

= $83.293 \times 10^{-3}$ g

= 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore, 40 g NaOH = 122 g benzoic acid

So, 0.0832 g NaOH = $\frac{122 g}{40 g} \times 0.0832 g$

= 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

$\frac{0.253 g}{0.3471 g} \times 100$

= 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

4 0

3 years ago

Argon has a pressure of 34.6 atm. It is transferred to a new tank with a volume of 456 L and pressure of 2.94 atm. What was the

NemiM [27]

Answer:

38.75 L

Explanation:

From the question,

Applying Boyles Law,

PV = P'V'....................... Equation 1

Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.

make V the subject of the equation

V = P'V'/P.................... Equation 2

Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.

Substitute these values into equation 2

V = (456×2.94)/34.6

V = 38.75 L

3 0

3 years ago

How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?

Veseljchak [2.6K]

Are produced 72 grams of water in this reaction.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

$Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2$

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

$MM_{Ca(OH)_2} = 74.1g/mol$

$MM = \frac{g}{mol}$

$74.1 = \frac{35.8}{mol}\\mol = 2$

So, if there are 2 mols of Ca(OH)2:

Ca(OH)2 | H2O

$\frac{1mol}{2mol} =\frac{2mol}{xmol}$

$x = 4mol$

Finally, just find the number of grams of water using your molar mass:

$MM_{H_2O} = 18g/mol$

$18= \frac{m}{4}\\m = 72g$

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237

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2 years ago

2) Pick the statement about the Bohr model of the hydrogen atom that is NOT true. A) The energy of each Bohr orbit is quantized.

DochEvi [55]

I think the answer would be c

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3 years ago

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