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snow_lady [41]
2 years ago
12

A student placed equal volumes of honey and of water in two, identical, open dishes, and left them at room temperature for 8 hou

rs. She observed that the amount of water decreased, but the amount of honey seemed unchanged. Knowing that honey is a highly concentrated solution of sugar in water, which statement should the student make to explain this phenomenon? Honey has a much lower vapor pressure than pure water has. So, pure water evaporates at a much higher rate. Honey has a much higher vapor pressure than water has. So, water evaporates at a much higher rate. Honey has a much lower freezing point than water has. So, water evaporates at a much higher rate. Honey has no vapor pressure. So, water evaporates at a much higher rate.
Chemistry
2 answers:
Ahat [919]2 years ago
8 0

Answer: Honey has a much lower vapor pressure than pure water has. So, pure water evaporates at a much higher rate.

Explanation:

Ronch [10]2 years ago
5 0

Answer:

A

Explanation:

Edge.

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A 100.0g sample of nickel is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water a
Marianna [84]

Answer:

0.429 J/g.°C

Explanation:

Step 1: Calculate the heat absorbed by the water (Qw)

We will use the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in the temperature

Qw = 4.184 J/g.°C × 150. g × (29.8°C-25.0°C) = 3012 J

Step 2: Calculate the heat released by the sample of nickel

According to the law of conservation of energy, the sum of the heat lost by the sample of nickel and the heat absorbed by the water is zero.

Qw + QNi = 0

QNi = -Qw = -3012 J

Step 3: Calculate the specific heat capacity of nickel

We will use the following expression.

QNi = c × m × ΔT

c = QNi/m × ΔT

c = -3012 J/100.0 g × (29.8°C-100.0°C) = 0.429 J/g.°C

6 0
2 years ago
The following are placed in a beaker weighing 39.457 g:
pickupchik [31]

Answer:

48.4 g

Explanation:

3 0
3 years ago
What happens to your upper arm muscles when you bend your arm at the elbow to eat your favorite sandwich.
Luda [366]
 Hello there,

I was going to say. . ." Who cares, Just eat the darn sandwich, if you love your favorite sandwich, who care what happens to your elbow's. But anyways the correct answer is the fulcrum in your arm levers the joints in your body. This causes there to be a friction between the <span>two muscles, causing your elbow to properly bend.

Hope this helps.

~Twizzie

And a little 'humor' is fine,Right! :D
</span><span>
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7 0
3 years ago
2.70g of aluminium was heated in oxygen until there was no further gain oxide ash formed had a mass of 5.10g. Deduce the empiric
Anarel [89]

The empirical formula is Al₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

Aluminium + oxygen ⟶ aluminium oxide

  2.70 g     +   x g      ⟶       5.10 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

2.70 g + <em>x</em> g ⟶ 5.10 g

<em>x</em> = 5.10 – 2.70 = 2.40

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

<em>Moles of Al</em> = 2.70 g Al × (1 mol Al/(26.98 g Al) = 0.1001 mol Al

<em>Moles of O</em> = 2.40 g O × (1 mol O/16.00 g O) = 0.1500 mol 0

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Al:O = 0.1001:0.1500 = 1:1.499

<em>Step 4</em>. Multiply each number by a factor that makes the ratio close to whole numbers

<em>Multiply</em> by 2. Then

Al:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Al₂O₃

8 0
2 years ago
When an automobile engine starts, the metal parts immediately begin to absorb heat released during the combustion of gasoline. H
Eddi Din [679]

Answer:

H = 4,034,250 J

Explanation:

Mass, m = 165kg = 165,000g (Converting to grams)

Initial temperature = 15.7°C

Final temperature = 95.7°C

Temperature change, ΔT = 95.7 - 15.7 = 50°C

Specific heat capacity, c = 0.489 J/g·°C

Heat = ?

All the parameters are related with the equation below;

H = m * c * ΔT

H = 165000 * 0.489  * 50

H = 4,034,250 J

6 0
3 years ago
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