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77julia77 [94]
2 years ago
8

If it takes 25.0 mL of 0.050 M HCl to neutralize 34.5 mL of NaOH solution, what is the molarity of the NaOH solution?

Chemistry
1 answer:
Serhud [2]2 years ago
8 0

The molarity of the NaOH solution is 0.036 M

First, we will write the balanced chemical equation for the reaction

The balanced equation of reaction between HCl and NaOH is

HCl + NaOH → NaCl + H₂O

In the balanced chemical equation above,

It means 1 mole of HCl is required to completely neutralize 1 mole of NaOH

To determine the molarity of the NaOH solution,

We will determine the number of moles of HCl that reacted

From the question,

Volume of HCl = 25.0 mL = 0.025 L

Concentration of HCl = 0.050 M

From the formula

Number of moles = Concentration × Volume

Then,

Number of moles of HCl = 0.050 × 0.025

Number of moles of HCl = 0.00125 moles

This means 0.00125 moles of HCl reacted with 0.00125 moles of NaOH

Now, to determine the molarity (that is concentration) of NaOH,

Number of moles of NaOH = 0.00125 moles

Volume of NaOH = 34.5 mL = 0.0345 L

From the formula

Number of moles = Concentration × Volume

Then,

Concentration = \frac{Number \ of \ moles }{Volume}

Concentration \ of \ NaOH = \frac{0.00125}{0.0345} \\

∴ Concentration of NaOH = 0.03623 M

Concentration of NaOH = 0.036 M

Hence, the molarity of the NaOH solution is 0.036 M

Learn more here: brainly.com/question/25008908

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Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

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Given that density of the vinegar is same is that of water =  1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

Density=\frac{Mass}{Volume}

1 g/mL=\frac{100 g}{V}

V = 100 mL = 0.1 L

Moles of acetic acid =\frac{4 g}{60.052 g/mol}=0.0666 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}

M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0
3 years ago
a gas sample occupies a volume of 140 mL at a temperature of 296 K and a pressure of 98.2kPa. how many moles of gas are there? s
Tamiku [17]

Answer:

0.00559 mol

Explanation:

The following data were obtained from the question:

V = 140mL = 0.14L

T = 296K

P = 98.2kPa = 98200Pa

Recall: 101325Pa = 1atm

98200Pa = 98200/101325 = 0.97atm

R = 0.082atm.L/Kmol

n =?

The number of mole (n) can be obtained as follows:

PV = nRT

n = PV /RT

n = (0.97x0.14)/(0.082x296)

n = 0.00559 mol

Therefore, the number of mole of the gas present is 0.00559 mol

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3 years ago
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Jobisdone [24]

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Explanation:

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What happens to the electrons in an ionic bond?
Anton [14]

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Explanation:

3 0
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telo118 [61]

Answer:

0.086

Explanation:

A 5.2 molal aqueous solution of methyl alcohol indicates that 5.2 moles of methyl alcohol are present in 1 kilogram (or 1000 g) of water. Water has a molecular weight of 18 g/mol.

(100g)/18g/mol=55.56 mol

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1 year ago
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