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sveta [45]
2 years ago
8

The County Seaters’ basketball team won 14 games and lost 11 games this season. What percent of its games did the County Seaters

win?
Mathematics
2 answers:
marysya [2.9K]2 years ago
7 0

Answer:

78.57% (79% If you round)

Step-by-step explanation:

tigry1 [53]2 years ago
5 0

The County Seaters’ basketball team won 14 games and lost 11 games this season. What percent of its games did the County Seaters win?

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Question
Vlada [557]

Answer:

(-6,4)

Step-by-step explanation:

You started at (-4,2)  The first number in the ordered pair moves the number left and right and the second number moved the point up and down.

We are first told to move the point 2 units to the left.  -4 is my left right number.  If I am at -4 and I go to unites to the left, I will be at -6.  My new point is now (-6,2).  Next we are told to go up 2.  The 2 number in my ordered pair tells me that I am 2 above the x axis.  Now I am going to go two more units up.  I am now at 4, so my new ordered pair after the translation is (-6,4)

8 0
1 year ago
6 4/5 + 3 2/3<br>add and simplify ​
hram777 [196]

Answer:

10 3/5

Step-by-step explanation:

6 4/5 + 3 4/5

First convert to improper fraction,

34/5 + 19/5

Then add the improper fractions,

=>53/5

Then convert improper fraction to mixed fraction,

=> 53/5 = 10 3/5

5 0
2 years ago
What degree of rotation is represented on this matrix
Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, -90^{\circ}

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}

Given the matrix: \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

Now, equate the given matrix with standard matrix we have;

\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix} =  \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

On comparing we get;

\cos \theta = 0       and -\sin \theta =1  

As,we know:

  • \cos \theta = \cos(-\theta)
  • \sin(-\theta) = -\sin \theta

\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})

we get;

\theta = -90^{\circ}

and

\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})

we get;

\theta = -90^{\circ}

Therefore, the degree of rotation is, -90^{\circ}

7 0
3 years ago
Can you help?
Ber [7]
-5 1/3, -2 1/2, 3.75, 4.2 ( this is the order from least to greatest)
5 0
3 years ago
I need help with number 10 ASAP
anzhelika [568]

i'm 75% sure the answer is C hope this helps


3 0
3 years ago
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