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Leona [35]
2 years ago
13

2 kg Use 10 m/s2 for g

Physics
1 answer:
Iteru [2.4K]2 years ago
6 0

Answer:

See below

Explanation:

At point A    the PE = mgh = 2 * 10 * 1 = 20 J

  at point B, all of the PE , 20 J , is converted to Kinetic Energy

KE = 1/2 m v^2

20 = 1/2 (2)(v^2 )

20 = v^2     v = sqrt 20 = 4.47 m/s

for the friction part

 vf = vo t  + 1/2 a t^2      vf = final velocity = 0 (stopped)

                                       vo = original velocity = 4.47 m/s  

                                         a = -1 m/s^2

  0 = 4.47 t + 1/2 (-1) t^2

            - .5t^2  + 4.47 t = 0

                 t ( -.5t+ 4.47) = 0    shows t =  4.47/.5 = 8.9 seconds

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Therefore,

(18\ kg.m^2)\omega_1 = (3.6\ kg.m^2)(1.67\ rev/s)\\\\\omega_1 = \frac{(3.6\ kg.m^2)(1.67\ rev/s)}{(18\ kg.m^2)}\\\\\omega_1 = \frac{\theta_1}{t_1} =  0.333\ rev/s\\\\\theta_1 = (0.333\ rev/s)t_1

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θ₁ = revolutions if she had not tucked at all = ?

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\theta_1 = (0.333\ rev/s)(1.5\ s)\\

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4 0
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Describe the formation of the land, the atmosphere, and the oceans of earth
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Answer:

plz brainliest

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Explanation:

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