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Stells [14]
2 years ago
13

If 2 objects are moved by the same force (F):

Physics
2 answers:
kipiarov [429]2 years ago
8 0

Answer:y=mx+b 58+5

Explanation:

JulijaS [17]2 years ago
8 0

Answer:

y=mx+b 58+5

Explanation:

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A student throws a 120 g snowball at 7.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of
mr Goodwill [35]

Answer:

The magnitude of the average force on the wall during the collision is 6 N.

Explanation:

Given;

mass of snowball, m = 120 g = 0.12 kg

velocity of the snowball, v = 7.5 m/s

duration of the collision between the snowball and the wall, t = 0.15 s

Magnitude of the average force can be calculated by applying Newton's second law of motion;

F = ma

where;

a is acceleration = v / t

a = 7.5 / 0.15

a = 50 m/s²

F = ma

F = 0.12 x 50

F = 6 N

Therefore, the magnitude of the average force on the wall during the collision is 6 N.

4 0
3 years ago
How are weather satellites and weather stations similar?
alexandr402 [8]
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3 years ago
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Dmitry [639]

Answer:

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Explanation:

5 0
3 years ago
Read 2 more answers
Object 1 has a mass of 3m and is moving to the right at a velocity of
andrew11 [14]

Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

6 0
2 years ago
A missile is launched upward with a speed that is half the escape speed. What height (in radii of Earth) will it reach?
timofeeve [1]

Answer:

The height (h) will be: \frac{3}{4}R =h  

Explanation:

The scape speed equation is given by:

v_{scape}=\sqrt{\frac{2GM}{R}}

Now, the speed of the missile is

v_{missile}=\frac{1}{2}v_{scape}

v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}

Using the conservation of energy, we can find the maximu height of the missile.

E_{i}=E_{f}

\frac{1}{2}mv_{scape}^{2}-mgR =-mgh

\frac{1}{2}\frac{2GM}{4R}-gR =-gh

\frac{GM}{4R}-gR =gh

Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.

\frac{1}{4}gR-gR =-gh

\frac{1}{4}R-R =-h    

Therefore the height (h) will be:

\frac{3}{4}R =h    

I hope it helps you!

4 0
2 years ago
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