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Stells [14]
3 years ago
13

If 2 objects are moved by the same force (F):

Physics
2 answers:
kipiarov [429]3 years ago
8 0

Answer:y=mx+b 58+5

Explanation:

JulijaS [17]3 years ago
8 0

Answer:

y=mx+b 58+5

Explanation:

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Four model rockets are launched in a field. The mass of each rocket and the net force acting on it when it launches are given in
kondor19780726 [428]

Answer:

Rocket 2 has highest acceleration.

Explanation:

Net force,

F = mass (m) × acceleration (a)

We have,

m₁ = 4.25 kg and F = 120 N

a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{120}{4.25}\\\\a_1=28.23\ m/s^2

m₂ = 3.25 kg, F₂ = 120 N

a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{120}{3.25}\\\\a_2=36.92\ m/s^2

m₃ = 5.5 kg, F₃ = 120 N

a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{120}{5.5}\\\\a_3=21.81\ m/s^2

m₄ = 4.5 kg, F₄ = 120 N

a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{120}{4.5}\\\\a_4=26.66\ m/s^2

Hence, it can be seen that the highest acceleration is of rocket 2.

7 0
3 years ago
A hockey puck moving at 0.4600 m/s collides with another puck that was at rest. The pucks have equal mass. The first puck is def
Sladkaya [172]

Answer:

Speed =0.283m/ s

Direction = 47.86°

Explanation:

Since it is a two dimensional momentum question with pucks having the same mass, we derive the momentum in xy plane

MU1 =MU2cos38 + MV2cos y ...x plane

0 = MU2sin38 - MV2sin y .....y plane

Where M= mass of puck, U1 = initial velocity of puck 1=0.46, U2 = final velocity of puck 1 =0.34, V2 = final velocity of puck 2, y= angular direction of puck2

Substitute into equation above

.46 = .34cos38 + V2cos y ...equ1

.34sin38 = V2sin y...equ2

.19=V2cos Y...x

.21=V2sin Y ...y

From x

V2 =0.19/cost

Sub V2 into y

0.21 = 0.19(Sin y/cos y)

1.1052 = tan y

y = 47.86°

Sub Y in to x plane equ

.19 = V2 cos 47.86°

V2=0.283m/s

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Answer:

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Explanation:

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