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Helen [10]
2 years ago
7

Tasks

Physics
1 answer:
barxatty [35]2 years ago
7 0

Answer:

NE DIYON INGILIZ MISIN SEN

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A person travels by car from one city to another with different constant speeds between pair of cities. She drives for 36 min at
Softa [21]

 Change minutes to hrs, divide by 60:
30 min = .50 hrs
45 min = .75 hrs
12 min = .20 hrs
----------------
total + 1.45 hrs, total travel time
:

let a = average speed for the trip
:
Write a dist equation, dist = speed * time
:
80(.5) + 100(.20) + 40(.75) = 1.45a
40 + 20 + 30 = 1.45a
90 = 1.45a
a =
a = 62.069 km/h, for the entire trip
and
90 km is the total distance 

3 0
3 years ago
How do reflection and refraction of waves affect communication?​
romanna [79]

Answer:

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

5 0
3 years ago
Read 2 more answers
8. Three grams of Bismuth-218 decay to 0.375 grams in one hour. What is the half-
Evgen [1.6K]

Answer: 0.333 h

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula</u>:  

A=A_{o}.2^{\frac{-t}{H}} (1)  

Where:  

A=0.375 g is the final amount of the material  

A_{o}=3 g is the initial amount of the material  

t=1 h is the time elapsed  

H is the half life of the material (the quantity we are asked to find)  

Knowing this, let's substitute the values and find h from (1):

0.375 g=(3 g)2^{\frac{-1h}{H}} (2)  

\frac{0.375 g}{3 g}=2^{\frac{-1h}{H}} (3)  

Applying natural logarithm in both sides:

ln(\frac{0.375 g}{3 g})=ln(2^{\frac{-1 h}{H}}) (4)  

-2.079=-\frac{1 h}{H}ln(2) (5)  

Clearing H:

H=\frac{-1h}{-2.079}(0.693) (6)  

Finally:

h=0.333 h This is the half-life of the Bismuth-218 isotope

4 0
3 years ago
For a standard production car, the highest road-tested acceleration ever reported occurred in 1993, when a Ford RS200 Evolution
Ann [662]

Answer:

a = 8.06 m/s²

Explanation:

The acceleration of this car can be found using the first equation of motion:

v_f = v_i + at\\\\a = \frac{v_f-v_i}{t}

where,

a = acceleration = ?

vf = final speed = 26.8 m/s

vi = initial speed = 0 m/s

t = time = 3.323 s

Therefore,

a = \frac{26.8\ m/s-0\ m/s}{3.323\ s}

<u>a = 8.06 m/s²</u>

3 0
2 years ago
If a certain gas occupies a volume of 12 l when the applied pressure is 6.0 atm , find the pressure when the gas occupies a volu
dolphi86 [110]
From Boyle's law, the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature. 
Therefore; P1V1 =P2V2; where PV is a constant
hence; 12 × 6 = 3× p2
           p2 = 72/3
                = 24 atm
Therefore; the new pressure will be 24 atm
5 0
3 years ago
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