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jasenka [17]
3 years ago
9

How to keep my family safe during a hurricane?

Physics
1 answer:
alexdok [17]3 years ago
8 0

If you are not advised to evacuate or are unable to do so safely, stay indoors, away from windows, skylights and doors. Continue to monitor weather reports and do not go outside until the storm has passed. And, to protect your children from seeing too many sights and images of the hurricane, limit media exposure.

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Sloan [31]

The first and third choices on the list will attract, because UNlike poles are facing across the gap.

Choice #1: . . . [S]-----[N] . . . [S]-----[N]

Choice #3: . . . [N]-----[S] . . . [N]-----[S]

8 0
3 years ago
Read 2 more answers
1. A body has a velocity of 72 km/hr. Find its value in m/s.
CaHeK987 [17]

72 Km/hr

= 72000 m/ 60×60 s

= 72000 m/ 3600 s

= 20 m/s

Answer is 20 m/s.

Hope it helps! Please do comment

8 0
3 years ago
Good afternoon.....from bangladesh....
Step2247 [10]

Answer:

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Explanation:

4 0
3 years ago
Read 2 more answers
A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i
sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, v_{Ci}=25\ m/s

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0
3 years ago
3.
kozerog [31]

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