Answer:=14,160 kJ
Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below
Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase
C MPa m^3/kg kJ/kg kJ/kg
1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture
2 260 4.689 0.0422 2599 2797 1 Saturated Vapor
The mass initially contained in the tank is m1 = V/v1
m1 =0.85 m^3 /0.02993 m^3 /kg
= 28.4 kg
The mass finally contained in the tank is
m2 =V2/v
= 0.85 m^3 /0.0422 m^3 /kg
= 20.14 kg
The heat transfer is then
Qcv = m2u2 − m1u1 − he(m2 − m1)
Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ
Weight=100N
SF=0.4
KF=0.3
Magnitude?
0.4 x 0.3 = 0.12
0.12x100=12
Ans =20
Answer:CANT SEE THE PICTURE
ch
Explanation:
NEED A BETTER PHOTO
Answer:
Force = 485000 Newton.
Explanation:
Given the following data;
Mass = 485000 kg
Initial velocity = 20m/s
Final velocity = 25m/s
Time, t = 5 seconds
To find the force;
First of all, we would calculate the acceleration of the train i.e the rate of change of the velocity of the train with respect to time.
Mathematically, acceleration is given by the equation;


Where;
a is acceleration measured in 
v and u is final and initial velocity respectively, measured in 
t is time measured in seconds.
Substituting into the equation, we have;
Acceleration = (25 - 20)/5
Acceleration = 5/5
Acceleration = 1m/s²
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Force = mass * acceleration
Force = 485000 * 1
Force = 485000 Newton.
Car designers will more than likely go back to the lab and change certain aspects of the car (Thickness of body, design of the vehicle's frame, etc.), thus making it more durable.