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3 years ago

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Chemistry

1 answer:

Naddik [55]3 years ago

8 0

Answer:

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Explanation:

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What is water in the form of a gas called?

skelet666 [1.2K]

It is generally referred to as ‘Steam’

Hope this helps and have a happy Friday!

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3 years ago

Read 2 more answers

A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve

Helen [10]

Answer:

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

Explanation:

The differential equation is given as:

$\frac{dC}{dt} = r- kC$

$\frac{dC}{r- kC} = dt$

Taking integral of both sides; we have:

$\int\limits \frac{dC}{r- kC} = \int\limits dt$

$-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD$

$r-kC=e^{-kt-kD}$

$r-kC=e^{-kt}e^{-kD}$

$r-kC=Ae^{-kt}$

$kC=r-Ae^{-kt}$

$C=\frac{r}{k}-\frac{A}{k}e^{-kt}$

$C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}$ ------- equation (1)

If C(0)= $C_o$ ; we have:

C(0)= $\frac{r}{k}-\frac{A}{k}e^0$ (where; A is an integration constant)

$C_o = \frac{r}{k}- \frac{A}{k}$

$C_o=\frac{r-A}{k}$

$kC_o=r-A$

$A=r-kC_o$

Substituting $A=r-kC_o$ into equation (1); we have;

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

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4 years ago

We are trying to build a good model of the _____________ that are happening on the tectonic plates under us.

Arturiano [62]

Answer:

scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.

Explanation:

i'm in the 7th grade

8 0

3 years ago

A chemist needs 10 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%,

mojhsa [17]

Answer:

a) 1 litre of 10% solution and 7 litre of 20% solution

b) 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) 3.75 litres of 50% solution and 6.25 litres of 20% solution

Explanation:

Given:

chemist needs = 10 liters of a 25% acid solution

Concentration of three solutions that are to be mixed = 10%, 20% and 50%.

Solution:

A) Use 2 liters of the 50% solution

Let us mix this with 10% and 20% solution

They will have to equal 8 litres

Let x=20% solution

Then (8-x) =10%

So the equation becomes,

10%(8-x)+ 20%x+50%(2)=25(10)

(0.1)(8-x) +0.2x+0.50(2)= 0.25(10)

0.8-0.1x+0.2x+1.0=2.5

0.2x-0.1x=2.5-0.8-1.0

0.1x=0.7

$x=\frac{0.7}{0.1}$

x= 7

so, 8-x = 8 -7= 1 litre of 10% solution and 7 litre of 20% solution

B)Use as little as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+20%(10-x)=25%(10)

0.50x+0.2(10-x)=0.25(10)

0.5x+2.0-0.2x=2.5

0.3x=2.5-2.0

0.3x=0.5

$x=\frac{0.5}{0.3}$

x=1.67

now (10-x)=(10-1.67)=8.33

so there will be 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) ) Use as much as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+10%(10-x)=25%(10)

0.50x+0.1(10-x)=0.25(10)

0.5x+1.0-0.1x=2.5

0.4x=2.5-1.0

0.4x=1.5

$x=\frac{1.5}{0.3}$

x=3.75

Now, (10-x)=(10- 3.75)=6.26

So there will be 3.75 litres of 50% solution and 6.25 litres of 20% solution

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3 years ago

What is the total charge of all the protons in 2.2 mol of he gas?

Tasya [4]

To determine the total charge of the protons in the gas, we need to know the number of protons that are present. We use Avogadro's number to know such value. We do as follows:

2.2 mol ( 6.022x10^23 protons / 1 mol ) = 1.325x10^24 protons

Total charge = 1.6021766208×10^−19 C (1.325x10^24) = 212262.77 C

3 0

3 years ago