Which property of potential energy distinguishes it from kinetic energy?
1 answer:
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Answer:
Boron (B) is the element whose IE matches with our data.
Electronic Configuration of boron:
Explanation:
Ionization Energy (IE):
It is the minimum amount of energy which is required to remove the lose electron. If the electron is closer to the nucleus then greater amount of energy is required to remove the electron.
If we look from left to right in a period, ionization energy increases due stability of valance shell.
From the data given to us:
IE₁ = 801
IE₂ = 2427
IE₃ = 3659
IE₄ = 25,022
IE₅ = 32,822
Boron (B) is the element whose IE matches with our data.
Electronic Configuration of boron:
Boron has 5 electrons (3 in valance shell) that's why it has 5 Ionization Energies.
Answer:
<h2>18 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
volume = final volume of water - initial volume of water
volume = 62 - 52 = 10 mL
From the question we have
We have the final answer as
<h3>18 g/mL</h3>Hope this helps you
Answer:
The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>
Explanation:
<u>According to the ideal gas equation: </u>
for an ideal gas,
and
Here, P: total pressure of the gases = 2.14 atm
V: total volume of the gases = 6.68 L
T: temperature = 19 °C = 19+273.15 = 292.15K (∵ 0°C = 273.15K)
R: gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹
: total number of moles of gases
<u>To calculate the total number of moles of gases</u>:
= <u>0.5963 moles</u>
Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂
<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g
molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol
Therefore, = n_{1}+n_{2} = (w₁ ÷ m₁) + (w₂ ÷ m₂)
⇒ 0.5963 mol = (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)
⇒ 0.5963 mol = (0.3817mol) + (w₂ ÷ 2.016 g/mol)
⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)
⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)
⇒ w₂ = 0.433 g
<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>