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diamong [38]
3 years ago
15

What is water in the form of a gas called?

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
8 0
It is generally referred to as ‘Steam’

Hope this helps and have a happy Friday!
netineya [11]3 years ago
6 0

Answer:

Vapor

Explanation:

Water can occur in three states: solid (ice), liquid, or gas (vapor). ... Water as a gas—vapor is always present in the air around us. You cannot see it. When you boil water, the water changes from a liquid to a gas or water vapor. As some of the water vapor cools, we see it as a small cloud called steam.

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Write the word equation for the chemical reaction: Zn(s)+2HCl2(aq)--->ZnCl2(aq)+H2(g)
Vikki [24]
Zn(s) + 2HCl(aq) = ZnCl₂(aq) + H₂(g)

zinc + hydrochloric acid = zinc chloride + hydrogen
4 0
3 years ago
a chemistry teacher adds 50.0 ml of 1.50 m h2so4 solution to 200 ml of water. What is the concentration of the final solution?
nevsk [136]

Answer:0.300M

Explanation:1) Data:

a) Initial solution

M = 1.50M

V = 50.0 ml = 0.050 l

b) Solvent added = 200 ml = 0.200 l

2) Formula:

Molarity: M = moles of solute / volume of solution is liters

3) Solution:

a) initial solution:

Clearing moles from the molarity formula: moles = M × V

moles of H₂SO₄ = M × V = 1.5M × 0.050 l = 0.075 mol

b) final solution:

i) Volumen of solution = 0.050 l + 0.200l = 0.250l

ii) M = 0.075 mol / 0.250 l = 0.300M ← answeer

5 0
3 years ago
What do cubic measurements, live cm3, mesure?"<br> O length<br> volume
anygoal [31]
The answer is volume.
6 0
3 years ago
A device that does work in a circuit is called what ?
zavuch27 [327]
These are called resistors. 
7 0
3 years ago
Read 2 more answers
A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
kondor19780726 [428]

Answer:

The final volume of the cylinder is 1.67 L

Explanation:

Step 1: Data given

Initial volume = 0.250 L

external pressure = 2.00 atm

Expansion does 288 J of work on the surroundings

Step 2: Definition of reversible work:

Wrev = -P(V2-V1) = -288 J

The gas did work, so V2>V1  (volume expands) and the work has a negative sign.(Wrev<0)

V2 = (-Wrev/P)  + V1

⇒ with Wrev = reverse work (in J)

⇒ with P = the external pressure (in atm)

⇒ with V1 = the initial volume

We can see that your pressure is in  atm  and energy in J

To convert from J to L * atm we should use a convenient conversion unit using the universal gas constants :

R = 8.314472 J/mol *K and R= 0.08206 L*atm/K*mol

V2 =- (-288 J * (0.08206 L*atm/K*mol  /8.314 J/mol *K))/2.00 atm  + 0.250L

V2 = 1.67 L

The final volume of the cylinder is 1.67 L

8 0
3 years ago
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