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Naily [24]
3 years ago
14

For each of the sites specified in the molecules, select whether the site is nucleophilic, electrophilic, or neither. Compound A

: The indicated site is a carbon in cyclohexane which is bonded to a bromine and a hydrogen. The indicated carbon in compound A is nucleophilic. neither electrophilic nor nucleophilic. electrophilic. Compound B: The indicated site is the double bond in cyclohexene, a 6 carbon ring with an internal alkene. The indicated bond in compound B is nucleophilic. electrophilic. neither electrophilic nor nucleophilic. Compound C: The indicated site is a carbon double bonded to oxygen, and bonded to O C H 3 and ethyl. The indicated carbon in compound C is neither electrophilic nor nucleophilic. nucleophilic. electrophilic. Compound D: THe indicated site is a carbon bonded to a methyl, two hydrogens and a carbon. There is a nitrogen atom two bonds away. The indicated carbon in compound D is neither electrophilic nor nucleophilic. electrophilic. nucleophilic. Compound E: The indicated site is an oxygen bonded to a carbon and a hydrogen. The indicated oxygen in compound E is neither electrophilic nor nucleophilic. electrophilic. nucleophilic.
Chemistry
1 answer:
GenaCL600 [577]3 years ago
6 0

Answer:

自分の仕事をするthis is your answe but translate it to english

Explanation:

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An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th
Vladimir [108]

<u>Answer:</u> The molarity of NO_3^- ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Cu(NO_3)_2.6H_2O) = 15.6 g

Molar mass of (Cu(NO_3)_2.6H_2O) = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M

As, 1 mole of (Cu(NO_3)_2.6H_2O) produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of NO_3^- ions = (2 × 0.153) = 0.306 M

Hence, the molarity of NO_3^- ions in the solution is 0.306 M

3 0
3 years ago
If total pressure of multiple gases is 512 mmHg, and the pressure of oxygen gas is 332 mmHg and the pressure of carbon monoxide
deff fn [24]

Answer: 67 mmHg

Explanation:

According to Dalton's Gas Law, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.

i.e Ptotal = P1 + P2 + P3 + .......

In this case,

Ptotal = 512 mmHg

P(oxygen) = 332 mmHg

P(carbon mono-oxide) = 113 mmHg

Remaining pressure (P3) = ?

To get P3, apply Dalton's Gas Law formula

Ptotal = P(oxygen) + P(carbon mono-oxide) + P3

512 mmHg = 332 mmHg + 113 mmHg + P3

512 mmHg = 445 mmHg + P3

P3 = 512 mmHg - 445 mmHg

P3 = 67 mmHg

Thus, the remaining pressure is 67 mmHg

5 0
3 years ago
How many total electrons can enter the set of 3p orbitals?<br> a. 3<br> b. 10<br> c. 2<br> d. 6
Sliva [168]

Answer:

For n=3 and l=1=p

It is 3p-orbital.

Magnetic quantum number m

l

have values from -l to +l and total of 2l+1 values.

Forl=1, m

l

values are:

m

l

=−1,0,1 for l=1; total m

l

values =3= Number of orbitals

Each orbital can occupy maximum of two electron

Number of electrons =2×3=6

Thus 6 electrons will show same quantum number values of n=3 and l=1.

Number of elements with last electron in 3p orbitals = 6

5 0
3 years ago
One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K
mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (s_{2} - s_{1}), in joules per gram-Kelvin, by the following model:

s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}} (1)

Where:

m - Mass, in kilograms.

c_{w} - Specific heat of water, in joules per kilogram-Kelvin.

T_{1}, T_{2} - Initial and final temperatures of water, in Kelvin.

If we know that m = 1\,kg, c_{w} = 4190\,\frac{J}{kg\cdot K}, T_{1} = 373.15\,K and T_{2} = 288.15\,K, then the change in entropy for the entire process is:

s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}

s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0
3 years ago
Combustion of hydrocarbons such as undecane (_____) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's
____ [38]

Answer: Undecane, C11H24 is a liquid hydrocarbon from the alkane homologue ( family ).

Explanation:

All hydrocarbons burn in air to release H20 and CO2.

Combustion of hydrocarbons thus increases the percentage of CO2 present in the atmosphere which is not so good as CO2 is a greenhouse gas. Greenhouse gases produce the greenhouse effect. The green house effect is the warming effect produced when gases present in the atmosphere allow and retain the radiation from the sun to the earth. Examples of greenhouse gases are CO2, CH4, SO3, NO, CFCs. The greenhouse effect leads to an increase in the temperature of the earth subsequently leading to (I) melting of large amounts of ice at the poles causing flooding. (II) rapid evaporation of water from Earth’s surface. (III) decrease in crop yield.

Also, high concentration CFCs ( chlorofluorocarbons ), as widely used in aerosols, coolants and packaging foams, in the atmosphere depletes the ozone layer leading to global warming. In 1996 an international agreement was reached for a complete ban of CFCs and more countries are now going Green ( using alternative energy sources ) so as to minimize emissions of these greenhouse gases

5 0
3 years ago
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