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Inessa05 [86]
1 year ago
5

Use the van der Waals equation and the ideal gas equation to calculate the volume of 1.000 mol of neon at a pressure of 500.0 at

m and a temperature of 355.0 K. Explain why the two values are different.
Chemistry
1 answer:
Ugo [173]1 year ago
4 0

Use the van der Waals equation and the ideal gas equation to calculate the volume of 1.000 mol of neon at a pressure of 500.0 atm and a temperature of 355.0 K.

The Van der Waals equation, also known as the Van der Waals equation of state, is an equation of state used in chemistry and thermodynamics that extends the ideal gas law to take into account the effects of molecular interaction as well as the finite size of the molecules in a gas.

We may build a new equation that better reflects real gas behavior by modifying the ideal gas law to include corrections for interparticle attractions and particle volumes. The van der Waals equation can be used to determine a gas's properties under less-than-ideal circumstances.

To learn more about the van der Waals equation please visit
brainly.com/question/13201335
#SPJ4

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If 23.7 g of Al(OH)3(s) are mixed with 29.5 g of H2SO4(s) and the reaction is run, answer the following questions:
expeople1 [14]

Aluminum hydroxide \text{Al}(\text{OH})_3 can behave as a base and neutralize sulfuric acid \text{H}_2\text{SO}_4 as in the following equation:

2\;\text{Al}(\text{OH})_3 \; (s) + 3\; \text{H}_2\text{SO}_4 \; (aq) \to \text{Al}_2(\text{SO}_4)_3 \; (aq) + 6 \; \text{H}_2\text{O} \; (l) (Balanced)


(a)

n = m/M. Thus the ratio between the number of moles of the two reactants available:

n(\text{Al}(\text{OH})_3, \text{supplied}) / n(\text{H}_2\text{SO}_4, \text{supplied})\\= [m(\text{Al}(\text{OH})_3)/ M(\text{Al}(\text{OH})_3)] / [n(\text{H}_2\text{SO}_4) / M(\text{H}_2\text{SO}_4)]\\= [23.7 / (26.98 + 3 \times(16.00 + 1.008))]/[29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00)]\\\approx 1.01

The value of this ratio required to lead to a complete reaction is derived from coefficients found in the balanced equation:

n(\text{Al}(\text{OH})_3, \text{theoretical}) / n(\text{H}_2\text{SO}_4, \text{theoretical}) = 2/3 \approx 0.667

The ratio for the complete reaction is smaller than that of the reactants available, indicating that the species represented on the numerator, \text{Al}(\text{OH})_3, is in excess while the one on the denominator, \text{H}_2\text{SO}_4, serves as the limiting reagent.


(b)

The quantity of water produced is dependent on the amount of limiting reactants available. 29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00) = 0.301 \; \text{mol} of sulfuric acid is supplied in this reaction as the limiting reagent. 6 moles of water molecules are produced for every 3 moles of sulfuric acid consumed. The reaction would thus give rise to 0.301 \; \text{mol} \times 6/3 = 0.602 \; \text{mol} of water molecules, which have a mass of 0.602 \times (2 \times 1.008 + 16.00) = 10.8 \; \text{g}.


(c)

\text{Percentage Yield}\\= \text{Actual Yield} / \text{Theoretical Yield} \times 100 \; \%\\= 2.21 / 10.8 \times 100 \; \%\\= 20.4 \; \%


(d)

The quantity of \text{Al}(\text{OH})_3, the reactant in excess, is dependent on the number of moles of this species consumed in the reaction and thus the quantity of the limiting reagent available. The consumption of every 3 moles of sulfuric acid, the limiting reagent, removes 2 moles of aluminum hydroxide \text{Al}(\text{OH})_3 from the solution. 0.301 \; \text{mol} of sulfuric acid is initially available as previously stated such that 0.301 \; \text{mol} \times 2/3 = 0.201 \; \text{mol}, or 0.201 \times (26.98 + 3 \time (16.00 + 1.008)) = 15.7 \; \text{g}, of \text{Al}(\text{OH})_3 would be eventually consumed.

23.7 - 15.7 = 8.0 \; \text{g} of \text{Al}(\text{OH})_3 would thus be in excess by the end of the reaction process.

3 0
3 years ago
What does the angular momentum quantum number determine?
damaskus [11]

The angular momentum quantum number determine the

<span>the energy of the electron on the outer shell
the possible number of electrons on particular orbital
the shape of the orbital
the orientation of the orbital</span>
6 0
3 years ago
Which of the following statements is always TRUE for the freezing of water?
Rom4ik [11]

ΔG > 0 is always true for the freezing of water.

Explanation:

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  • The entropy decreases as water freezes. This does not infringe the Thermodynamics second law. The second law doesn't suggest entropy will never diminish anywhere.
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3 0
3 years ago
50 points - I need this really soon! plz help
kirill115 [55]

Answer:

C.

Explanation:

Butane (C4H10) has 3 C-C bonds in the carbon chain and 10 C-H bonds

7 0
3 years ago
AWNSER FAST PLEASE
Ann [662]

Answer: The coefficients are 2, 2 and 1.

Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants.

The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for the given reaction is:

2H2o➡️2h2+o2

3 0
2 years ago
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