MgCl₂ & PbSO₄ is the correct product for the given double replacement reaction.
<h3>What is double displacement reaction?</h3>
In the double displacement reaction displacement of two substrate will take place among two reactants and formation of products takes place.
In the question, PbCl₂ reacts with MgSO₄ and displacement between the cations takes place and formation of MgCl₂ and insoluble precipitate PbSO₄ is formed.
Given reaction is represented as:
PbCl₂ + MgSO₄ → MgCl₂ + PbSO₄
According to the activity series, reactivity of Magnesium is more as compared to the lead atom. So lead is displaced by the magnesium atom and form the above given products.
Hence, option (3) is correct i.e. MgCl₂ & PbSO₄.
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<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the concentration of unknown phosphoric acid solution is 0.034 M
Answer:
<h3>There's no way for C8H8 to exist without double bonds. To fulfill the rule of the octet, four bonds must be formed by each carbon. This can only be done in C8H8 through the formation of double bonds.</h3>
Explanation:
Answer:
nuclear decay reactions and nuclear transmutation reactions
Explanation:
I believe the correct answer among the choices listed above is option C. <span>Methane burns in oxygen to yield carbon dioxide and water. In chemical symbols, it is represented as:
</span><span>CH4 + 2O2--> CO2 + 2H2O</span>