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3 years ago

7

17. An uncharged metal rod brought close to but not touching the cap of a charged electroscope caused decrease in the divergence

of the leaf. Explain this observation. (1 mk)

1 answer:

Furkat [3]3 years ago

3 0

Explanation:

Metals get charged by induction ,the charges are transferred from the electroscope causing earthing: Charges on the electroscope induce opposite charges on the conductor.

I want brainliest plz!!!

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If the pressure is 100,000 Pa, R is 8.314, the temperature is 300 K, and the number of moles of gas (n) is 100, what is the volu

djyliett [7]

We can solve the problem by using the ideal gas equation:
$pV=nRT$
where
p is the pressure of the gas
V is the volume of the gas
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas

For the gas in our problem, we have:
$p=100000 Pa$
$R=8.314 J mol^{-1} K^{-1}$
$T=300 K$
$n=100$

If we rearrange the equation and we put these numbers into it, we find the volume of the gas:
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3 years ago

0. The temperature of source is 500K with source energy 2003, what is the temperature of sink with sink energy 100 J? a. 500 K b

andreev551 [17]

Answer:

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3 years ago

A projectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat deser

sleet_krkn [62]

Answer:

Explanation:

Given

mass of projectile $m=6.8\ kg$

initial horizontal speed $u_x=14.5\ m/s$

height $h=26.7\ m$

Considering vertical motion

velocity gained by projectile during 26.7 m motion

$v^2-u^2=2 as$

v=final velocity

u=initial velocity

a=acceleration

s=displacement

$v^2-(0)^2=2\times (9.8)\times (26.7)$

$v=\sqrt{523.32}$

$v=22.87\ m/s$

Horizontal velocity will remain same as there is no acceleration

final velocity $v_{net}=\sqrt{(v)^2+(u_x)^2}$

$v_{net}=\sqrt{733.57}=27.08\ m/s$

Initial kinetic Energy $K_i=\frac{1}{2}mu_x^2$

$K_i=\frac{1}{2}\times 6.8\times (14.5)^2=714.85\ J$

Final Kinetic Energy $K_f=\frac{1}{2}mv_{net}^2$

$K_f=\frac{1}{2}\times 6.8\times (27.08)^2$

$K_f=2493.30\ J$

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is $W_g$

$W_g=\Delta K$

$W_g=2493.30-714.85=1778.45\ J$

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3 years ago