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aksik [14]
2 years ago
6

Determine the molecular formula of a compound with an empirical formula of NH2 and a formula mass of 32.06 amu

Chemistry
2 answers:
Lilit [14]2 years ago
4 0
N2H4

<span>Each nitrogen weighs 14.01 and each H weighs 1.01. !4.01+14.01+1.01+1.01 = 32.06 (roughly) </span>

NemiM [27]2 years ago
3 0

Answer:N2H4

Explanation: Empirical Formula, EF= NH2

Mass of the EF = mass of Nitrogen + mass of Hydrogen

EF = 14.007 + 1.008

= 15.015

Then, divide the given formula mass by the EF. That is,

32.06/15.015 = 2.135 = 2 (to the nearest whole number) ......... (1)

To get the molecular formula, multiple the empirical formula with the number from the equ (1) above.

Molecular formula = 2[NH2] = N2H4

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24 g of magnesium were burned in oxygen. The compound formed had a mass of 40 g. Explain why the mass had gone up.
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Answer :

According to the law of conservation of mass, the mass of reactants must be equal to the mass of products.

The balanced chemical reaction is,

Mg+\frac{1}{2}O_2\rightarrow MgO

As we know that the molar mass of magnesium is 24 g/mole, the molar mass of O_2 is 32 g/mole and the molar mass of magnesium oxide is 40 g/mole.

From the given balanced reaction, we conclude that

As, 1 mole of magnesium react \frac{1}{2} mole of oxygen to give 1 mole of magnesium oxide.

So, the mass of Mg is 24 g, the mass of O_2=\frac{1}{2}\times 32=16g and the mass of MgO is 40 g.

That means 24 g of Mg react with 16 g O_2 to give 40 g of MgO.

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3 years ago
A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w
Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

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c=5760J/^oC

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To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

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What are two functions of the cell membrane
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1 It gives the cell its structure

2 It regulates the materials that enter and leaves the cell

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