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2 years ago

The force of gravity on Jupiter is much stronger than the force of gravity on earth what is the answer?

Physics

2 answers:

Pachacha [2.7K]2 years ago

7 0

This would be true. On Jupiter you would weigh 234 pounds if you were 100 pounds on Earth.

Travka [436]2 years ago

4 0

The force of gravity on Jupiter is 24.79m/s2
earth is 9.807m/s2.

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what term describes the situation where the frequency of the wind match the frequency of the building? a. velocity b. resonance

saul85 [17]

The answer is B) resonance

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2 years ago

On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snoho

Svetlanka [38]

Answer: part a: 19.62m

part b: 19.62 m/s

part a: 2.83 secs

Explanation:If the air resistance is ignored then the swimmer experience free fall under gravity hence

u=0

a=9.81 m/s2

t=2 secs

$s=ut+0.5at^2$

s=h

$h=0*2+0.5*9.81*2^2\\h=19.62 meters$

Part b

$v=u+at\\v=0+9.81*2\\v=19.62m/s$

Part c

now we have h=2*19.62=39.24

$39.24=0+0.5*9.81*t^2\\t^2=8\\t=2.83 secs$

4 0

2 years ago

determine whether the following equations are dimensionally correct if not how can you make them dimensionally correct 1 /2 mv2

serg [7]

Answer:

$1 /2 mv^{2} =mgh$

Explanation:

The correct equation follows the law of conservation of energy where kinetic energy is all transformed to potential energy, since we know that kinetic energy is expressed as

$1 /2 mv^{2}$ while potential energy is mgh where m is the mass of the object, v is the velocity or speed of the object, g is acceleration due to gravity and h is the vertical height. Therefore, relating the two equations we should have $1 /2 mv^{2} =mgh$

6 0

2 years ago

Which contribution did Kepler make to viewing the solar system?

amm1812

He proposed the sun-centered model of the solar system.

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2 years ago

A block moving to the right on a level surface with friction is pulled by an increasing horizontal force also directed to the ri

KengaRu [80]

Answer:

e) True Yes both are constant

Explanation:

Let us propose the solution of the problem before reviewing the statements, we use Newton's second law

F - fr = m a

N- W = 0

N = mg

The equation for the force of friction is

fr = μ N

F - μ mg = m a

F = m (a- μ g)

Now let's review the claims

.a) False. Normal force and friction are constants.

.b) False. Both are constant.

.c) False. Both are constant.

d.) False

e) True Yes both are constant

6 0

2 years ago