Methane (CH 4 ) , ammonia (NH 3 ) , and oxygen () can reaci to form hydrogen cyanide (HCN) and water (H 2 O) according to this e
quation 2CH 4 +2NH 3 +3O 2 2HCN+6H 2 O How many grams of methane are required to produce 2 moles ? Use your periodic table to help you.
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1 answer:
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Answer:
113.8g
Explanation:
Statement of problem: mass of 1.946mole of NaCl
Given parameters:
Number of moles of NaCl = 1.946mole
Unknown: mass of NaCl
Solution
To find the mass of NaCl, we apply the concept of moles which expresses the relationship between number of moles and mass according to the equation below:
Number of moles =
To find the molar mass of NaCl:
the atomic mass of Na = 23g
atomic mass of Cl = 35.5g
Molar mass of NaCl = (23 + 35.5) = 58.5gmol⁻¹
Mass of NaCl = Number of moles x molar mass of NaCl
Mass of NaCl = 1.946 x 58.5 = 113.8g